json.decoder.JSONDecodeError: Expecting ',' delimiter: line 5 column 3 (char 105)
时间: 2024-04-14 13:24:23 浏览: 17
JSONDecodeError是一个JSON解码时可能出现的错误。具体来说,DecodeError: Expecting ',' delimiter: line 5 column 3 (char 105)表示在解析JSON字符串时,期望在第5行第3列(字符105)处找到逗号(,)作为分隔符,但实际上找到的字符不是逗号。
这个错误通常发生在JSON字符串中的某个地方缺少了逗号,导致解析器无法正确解析JSON数据。要解决这个错误,你需要检查JSON字符串的结构,确保每个元素之间都有逗号作为分隔符。
相关问题
json.decoder.JSONDecodeError: Expecting ',' delimiter: line 75 column 2
JSONDecodeError异常通常发生在解析JSON数据时,Python解析器期望在JSON对象或数组的元素之间看到逗号(','),但未找到逗号或者逗号的位置不正确。根据提供的引用内容,错误信息是"json.decoder.JSONDecodeError: Expecting ',' delimiter: line 75 column 2"。这意味着在JSON数据的第75行第2列位置上缺少了逗号。<span class="em">1</span><span class="em">2</span><span class="em">3</span>
#### 引用[.reference_title]
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json.decoder.JSONDecodeError: Expecting ':' delimiter: line 1 column 91 (char 90)
json.decoder.JSONDecodeError: Expecting ':' delimiter: line 1 column 91 (char 90)错误的原因是在第一行的第91个字符处缺少了冒号(:)分隔符。
为了解决这个问题,需要在正确的位置添加冒号(:)分隔符。在给定的示例中,冒号(:)应该在 "uid" 键和其对应的值之间添加。正确的JSON字符串应该是:
{ "uid": "1", "data": [ ["数据1", 86, 81], ["曼联", 74, 66], ["利物浦", 69, 99] ] } <span class="em">1</span><span class="em">2</span><span class="em">3</span>
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