用java实现剪刀石头布小游戏：编写一个剪刀石头布游戏的程序。程序启动后会随机生成0~2的随机数，分别代表剪刀、石头和布，玩家通过键盘输入剪刀、石头和布与电脑进行3轮的游戏，赢的次数多的一方为赢家。若三局皆为平局，则最终结果判为平局。

以下是使用Java实现剪刀石头布小游戏的基本步骤：

1. **创建抽象基类 Player**[^2]:

abstract class Player {
    public abstract String makeChoice(); // 基类定义选择行为
}

2. **定义具体玩家类 (Computer)**:

class Computer extends Player {
    private static final int[] choices = {0, 1, 2}; // 剪刀(0), 石头(1), 布(2)
    
    @Override
    public String makeChoice() {
        return "Scissors", "Stone", "Paper"[choices[new Random().nextInt(choices.length)]];
    }
}

3. **创建玩家类 (Human)**:

class Human extends Player {
    @Override
    public String makeChoice() {
        Scanner scanner = new Scanner(System.in);
        System.out.println("Choose: 1 for Rock, 2 for Paper, 3 for Scissors");
        int input = scanner.nextInt();
        return "Rock", "Paper", "Scissors"[input - 1]; // 用户输入映射到游戏选项
    }
}

4. **主游戏循环**:

public class Game {
    public static void main(String[] args) {
        Player computer = new Computer();
        Player human = new Human();
        
        int rounds = 3;
        int humanWins = 0, computerWins = 0;

        for (int i = 0; i < rounds; i++) {
            String humanChoice = human.makeChoice();
            String computerChoice = computer.makeChoice();

            if (humanChoice.equals(computerChoice)) {
                System.out.println("It's a tie!");
            } else if (isWinningMove(humanChoice, computerChoice)) {
                humanWins++;
                System.out.println("You win this round!");
            } else {
                computerWins++;
                System.out.println("Computer wins this round!");
            }
        }

        if (humanWins > computerWins) {
            System.out.println("You are the winner!");
        } else if (humanWins < computerWins) {
            System.out.println("Computer is the winner!");
        } else {
            System.out.println("It's a draw!");
        }
    }

    private static boolean isWinningMove(String human, String computer) {
        // 判断胜负逻辑：石头胜剪刀，剪刀胜布，布胜石头
        return human.equals("Stone") && !computer.equals("Scissors") ||
               human.equals("Scissors") && !computer.equals("Paper") ||
               human.equals("Paper") && !computer.equals("Rock");
    }
}