C#将0xFB,0x5C合并成FB5C并转成byte

在C#中，你可以通过位运算和字节拼接的方式来将两个十六进制数合并成一个字符串，然后转换为字节数组。这里是一个简单的示例：

byte[] combineAndConvert(byte num1, byte num2) {
    // 将两个十六进制数转换为整数
    int combinedInt = (int)num1 + (int)(num2 << 8); // num2左移8位是因为它的最高位在num1之后

    // 将整数转换为二进制字符串，然后去掉前导零
    string binaryString = combinedInt.ToString("X4").PadLeft(4, '0');

    // 转换为字节数组
    return Array.ConvertAll(binaryString.ToCharArray(), c => Convert.ToByte(c.ToString()));
}

// 使用示例
byte[] result = combineAndConvert((byte)0xFB, (byte)0x5C);

这个函数首先将两个输入的字节转换为整数（`num1`代表`0xFB`，`num2 << 8`相当于`0x5C00`），然后合成为一个新的整数。接着将这个整数转换为四位的十六进制字符串，并用'0'填充到四位。最后，将每个字符转换回字节。

相关问题

int main() { unsigned int v19; const unsigned char sbox0[256] ={0x63,0x7c,0x77,0x7b,0xf2,0x6b,0x6f,0xc5,0x30,0x01,0x67,0x2b,0xfe,0xd7,0xab,0x76,0xca,0x82,0xc9,0x7d,0xfa,0x59,0x47,0xf0,0xad,0xd4,0xa2,0xaf,0x9c,0xa4,0x72,0xc0,0xb7,0xfd,0x93,0x26,0x36,0x3f,0xf7,0xcc,0x34,0xa5,0xe5,0xf1,0x71,0xd8,0x31,0x15,0x04,0xc7,0x23,0xc3,0x18,0x96,0x05,0x9a,0x07,0x12,0x80,0xe2,0xeb,0x27,0xb2,0x75,0x09,0x83,0x2c,0x1a,0x1b,0x6e,0x5a,0xa0,0x52,0x3b,0xd6,0xb3,0x29,0xe3,0x2f,0x84,0x53,0xd1,0x00,0xed,0x20,0xfc,0xb1,0x5b,0x6a,0xcb,0xbe,0x39,0x4a,0x4c,0x58,0xcf,0xd0,0xef,0xaa,0xfb,0x43,0x4d,0x33,0x85,0x45,0xf9,0x02,0x7f,0x50,0x3c,0x9f,0xa8,0x51,0xa3,0x40,0x8f,0x92,0x9d,0x38,0xf5,0xbc,0xb6,0xda,0x21,0x10,0xff,0xf3,0xd2,0xcd,0x0c,0x13,0xec,0x5f,0x97,0x44,0x17,0xc4,0xa7,0x7e,0x3d,0x64,0x5d,0x19,0x73,0x60,0x81,0x4f,0xdc,0x22,0x2a,0x90,0x88,0x46,0xee,0xb8,0x14,0xde,0x5e,0x0b,0xdb,0xe0,0x32,0x3a,0x0a,0x49,0x06,0x24,0x5c,0xc2,0xd3,0xac,0x62,0x91,0x95,0xe4,0x79,0xe7,0xc8,0x37,0x6d,0x8d,0xd5,0x4e,0xa9,0x6c,0x56,0xf4,0xea,0x65,0x7a,0xae,0x08,0xba,0x78,0x25,0x2e,0x1c,0xa6,0xb4,0xc6,0xe8,0xdd,0x74,0x1f,0x4b,0xbd,0x8b,0x8a,0x70,0x3e,0xb5,0x66,0x48,0x03,0xf6,0x0e,0x61,0x35,0x57,0xb9,0x86,0xc1,0x1d,0x9e,0xe1,0xf8,0x98,0x11,0x69,0xd9,0x8e,0x94,0x9b,0x1e,0x87,0xe9,0xce,0x55,0x28,0xdf,0x8c,0xa1,0x89,0x0d,0xbf,0xe6,0x42,0x68,0x41,0x99,0x2d,0x0f,0xb0,0x54,0xbb,0x16}; const char* a3="UK*@3oKpFlVVnadsTfdA"; int v7=16; memcpy(&v19, a3, v7); for (int j = 0; j != 16; ++j ) *((_BYTE *)&v19 + j) = sbox0[*((unsigned *)&v19 + j)]; return 0; }输出v19值

根据代码可以看出，将字符串"a3"的前16个字符拷贝到一个unsigned int类型的变量v19中，并对v19进行一系列的sbox0变换。但是由于sbox0变换是按照字节进行的，因此需要先将v19的字节序进行转换。最终输出v19的值即可。

由于题目中没有给出字符串"a3"，因此无法得知v19的值。

#define CRC(crc,byte) (((crc) >> 8 ) ^ tabel[((crc) ^ (unsigned int) (byte)) & 0XFF]) static const uint16 tabel[256] = { 0X0000, 0XC0C1, 0XC181, 0X0140, 0XC301, 0X03C0, 0X0280, 0XC241, 0XC601, 0X06C0, 0X0780, 0XC741, 0X0500, 0XC5C1, 0XC481, 0X0440, 0XCC01, 0X0CC0, 0X0D80, 0XCD41, 0X0F00, 0XCFC1, 0XCE81, 0X0E40, 0X0A00, 0XCAC1, 0XCB81, 0X0B40, 0XC901, 0X09C0, 0X0880, 0XC841, 0XD801, 0X18C0, 0X1980, 0XD941, 0X1B00, 0XDBC1, 0XDA81, 0X1A40, 0X1E00, 0XDEC1, 0XDF81, 0X1F40, 0XDD01, 0X1DC0, 0X1C80, 0XDC41, 0X1400, 0XD4C1, 0XD581, 0X1540, 0XD701, 0X17C0, 0X1680, 0XD641, 0XD201, 0X12C0, 0X1380, 0XD341, 0X1100, 0XD1C1, 0XD081, 0X1040, 0XF001, 0X30C0, 0X3180, 0XF141, 0X3300, 0XF3C1, 0XF281, 0X3240, 0X3600, 0XF6C1, 0XF781, 0X3740, 0XF501, 0X35C0, 0X3480, 0XF441, 0X3C00, 0XFCC1, 0XFD81, 0X3D40, 0XFF01, 0X3FC0, 0X3E80, 0XFE41, 0XFA01, 0X3AC0, 0X3B80, 0XFB41, 0X3900, 0XF9C1, 0XF881, 0X3840, 0X2800, 0XE8C1, 0XE981, 0X2940, 0XEB01, 0X2BC0, 0X2A80, 0XEA41, 0XEE01, 0X2EC0, 0X2F80, 0XEF41, 0X2D00, 0XEDC1, 0XEC81, 0X2C40, 0XE401, 0X24C0, 0X2580, 0XE541, 0X2700, 0XE7C1, 0XE681, 0X2640, 0X2200, 0XE2C1, 0XE381, 0X2340, 0XE101, 0X21C0, 0X2080, 0XE041, 0XA001, 0X60C0, 0X6180, 0XA141, 0X6300, 0XA3C1, 0XA281, 0X6240, 0X6600, 0XA6C1, 0XA781, 0X6740, 0XA501, 0X65C0, 0X6480, 0XA441, 0X6C00, 0XACC1, 0XAD81, 0X6D40, 0XAF01, 0X6FC0, 0X6E80, 0XAE41, 0XAA01, 0X6AC0, 0X6B80, 0XAB41, 0X6900, 0XA9C1, 0XA881, 0X6840, 0X7800, 0XB8C1, 0XB981, 0X7940, 0XBB01, 0X7BC0, 0X7A80, 0XBA41, 0XBE01, 0X7EC0, 0X7F80, 0XBF41, 0X7D00, 0XBDC1, 0XBC81, 0X7C40, 0XB401, 0X74C0, 0X7580, 0XB541, 0X7700, 0XB7C1, 0XB681, 0X7640, 0X7200, 0XB2C1, 0XB381, 0X7340, 0XB101, 0X71C0, 0X7080, 0XB041, 0X5000, 0X90C1, 0X9181, 0X5140, 0X9301, 0X53C0, 0X5280, 0X9241, 0X9601, 0X56C0, 0X5780, 0X9741, 0X5500, 0X95C1, 0X9481, 0X5440, 0X9C01, 0X5CC0, 0X5D80, 0X9D41, 0X5F00, 0X9FC1, 0X9E81, 0X5E40, 0X5A00, 0X9AC1, 0X9B81, 0X5B40, 0X9901, 0X59C0, 0X5880, 0X9841, 0X8801, 0X48C0, 0X4980, 0X8941, 0X4B00, 0X8BC1, 0X8A81, 0X4A40, 0X4E00, 0X8EC1, 0X8F81, 0X4F40, 0X8D01, 0X4DC0, 0X4C80, 0X8C41, 0X4400, 0X84C1, 0X8581, 0X4540, 0X8701, 0X47C0, 0X4680, 0X8641, 0X8201, 0X42C0, 0X4380, 0X8341, 0X4100, 0X81C1, 0X8081, 0X4040 }; unsigned short CalcCRC(uint8 *data, uint32 size) { uint32 i; unsigned short crc = 0; for (i = 0; i < size; i++) { crc = CRC(crc, data[i]); } return crc; }

这段代码是用于计算CRC校验值的函数。CRC（Cyclic Redundancy Check）是一种常用的校验方法，用于验证数据在传输过程中是否发生错误。

该函数接受一个指向数据的指针和数据的大小作为参数，然后通过循环计算每个字节的CRC值，并最终返回计算得到的CRC校验值。

CRC宏定义中使用了一个名为tabel的常量数组，该数组包含256个16位的元素，用于存储预先计算好的CRC值。在计算CRC的过程中，使用了这个数组来查找对应字节的CRC值。

整个计算过程中，使用了一个循环和一个CRC宏定义。循环遍历数据中的每个字节，并通过调用CRC宏定义来计算每个字节的CRC值。最后将所有字节的CRC值累积起来，得到最终的CRC校验值。

注意，该代码中使用了uint8和uint32这两个类型，需要确保在使用之前进行正确的定义或包含相关的头文件。