scores={"zhangsan":45,"lisi":78,"wangwu":40,"zhouwu":96} highest=max() lowest=min() average=sum()/len(scores) highestperson=[name for name,score in () if score==hightest] print(highest,lowest,average,highestperson)
时间: 2023-06-17 09:08:46 浏览: 65
这段代码有一些错误,我帮你修正一下:
```python
scores = {"zhangsan": 45, "lisi": 78, "wangwu": 40, "zhouwu": 96}
highest = max(scores.values())
lowest = min(scores.values())
average = sum(scores.values()) / len(scores)
highestperson = [name for name, score in scores.items() if score == highest]
print(highest, lowest, average, highestperson)
```
这段代码用字典存储了四个人的成绩,然后通过内置函数 `max()`、`min()` 和 `sum()` 计算了最高分、最低分和平均分。其中 `max()`、`min()` 函数需要传入一个可迭代对象,这里用字典的 `values()` 方法获取了所有分数的值。计算平均分时,先求出所有分数的和,再除以人数。最后通过列表推导式找到了得最高分的人的姓名。
相关问题
if np.argmax(scores) == 5:
The code snippet you provided is incomplete and lacks context, so I cannot provide a specific answer. However, in general, the expression `np.argmax(scores)` returns the index of the maximum value in the `scores` array or tensor, and `if np.argmax(scores) == 5:` checks if the maximum value is located at index 5. Depending on the specific use case and implementation, the code may perform different actions or make different decisions based on this condition.
.已知一个包含一些同学成绩的字典("ZhangSan":45,"LiSi":78,"WangXiao": 96,"ZhaoQi":+65,+"Xiaobai":+90,+"ZhengHui":+78,
为了获取成绩字典中的最高分和最低分,可以使用Python内置的max()和min()函数。这两个函数都可以接受一个字典作为参数,并返回字典中的最大值和最小值。下面是一个例子:
```python
scores = {"ZhangSan":45,"LiSi":78,"WangXiao":96,"ZhaoQi":65,"Xiaobai":90,"ZhengHui":78}
max_score = max(scores.values())
min_score = min(scores.values())
print("最高分是:", max_score)
print("最低分是:", min_score)
```
输出结果为:
```
最高分是: 96
最低分是: 45
```