00:14:42 select studentid, name, achieve.courseid, coursename, coursecredit, coursetime from test.student, test.achieve, test.course where test.student.studentid = test.achieve.studentid and achieve.courseid = course.courseid LIMIT 0, 1000 Error Code: 1052. Column 'studentid' in field list is ambiguous 0.000 sec
时间: 2023-07-16 08:12:56 浏览: 191
这个错误的原因是你在查询语句中使用了多个表,并且这些表有相同的列名,导致数据库无法确定你要查询哪个表的该列。解决这个问题的方法是在查询语句中指定列所属的表,例如:
```
SELECT test.student.studentid, test.student.name, test.achieve.courseid, test.course.coursename, test.course.coursecredit, test.course.coursetime
FROM test.student, test.achieve, test.course
WHERE test.student.studentid = test.achieve.studentid AND test.achieve.courseid = test.course.courseid
LIMIT 0, 1000;
```
这样就可以避免列名冲突导致的错误。
相关问题
请修改这段代码:case 5: System.out.println("请输入学号:"); studentID=scanner.next(); Student student1=new Student(); school.removeStudent(student1); break; case 6: System.out.println("请输入学号:"); studentID=scanner.next(); System.out.println("请输入新学号:"); String newStudentID=scanner.next(); System.out.println("请输入新姓名:"); String newName=scanner.next(); Student student2=new Student(); school.modigyStudentInfo(student2, newStudentID, newName); break;
根据你提供的代码,我无法确定 `school` 是什么类型的对象,但是根据代码的语义,我猜测它是一个学校对象,具有删除学生和修改学生信息的功能。根据这个猜测,我对代码进行了修改,如下所示:
```
case 5:
System.out.println("请输入学号:");
studentID = scanner.next();
school.removeStudent(studentID);
break;
case 6:
System.out.println("请输入学号:");
studentID = scanner.next();
System.out.println("请输入新学号:");
String newStudentID = scanner.next();
System.out.println("请输入新姓名:");
String newName = scanner.next();
school.modifyStudentInfo(studentID, newStudentID, newName);
break;
```
主要的修改是将创建 `Student` 对象的代码删除,因为我们已经有了学号作为输入,不需要再创建一个新的学生对象。另外,我将修改学生信息的函数名从 `modigyStudentInfo` 修改为 `modifyStudentInfo`,并且将第一个参数改为了学号,以便更加准确地表示这个函数的作用。
请根据school类中这段代码:public void removeStudent(Student student) { studentList.remove(student); } public void modigyStudentInfo(Student student, String newStudentID, String newName) { student.setStudentID(newStudentID); student.setName(newName); }修改主类中下面这段代码:case 5: System.out.println("请输入学号:"); studentID=scanner.next(); Student student1=new Student(); school.removeStudent(student1); break; case 6: System.out.println("请输入学号:"); studentID=scanner.next(); System.out.println("请输入新学号:"); String newStudentID=scanner.next(); System.out.println("请输入新姓名:"); String newName=scanner.next(); Student student2=new Student(); school.modigyStudentInfo(student2, newStudentID, newName); break;
您需要对主类中的代码进行修改,使其可以正确地调用school类中的removeStudent和modigyStudentInfo方法。具体修改如下:
case 5:
System.out.println("请输入学号:");
studentID = scanner.next();
Student student1 = null;
for (Student s : school.getStudentList()) {
if (s.getStudentID().equals(studentID)) {
student1 = s;
break;
}
}
if (student1 == null) {
System.out.println("没有找到该学生!");
} else {
school.removeStudent(student1);
System.out.println("删除成功!");
}
break;
case 6:
System.out.println("请输入学号:");
studentID = scanner.next();
System.out.println("请输入新学号:");
String newStudentID = scanner.next();
System.out.println("请输入新姓名:");
String newName = scanner.next();
Student student2 = null;
for (Student s : school.getStudentList()) {
if (s.getStudentID().equals(studentID)) {
student2 = s;
break;
}
}
if (student2 == null) {
System.out.println("没有找到该学生!");
} else {
school.modigyStudentInfo(student2, newStudentID, newName);
System.out.println("修改成功!");
}
break;
在case 5中,我们首先通过循环找到需要删除的学生对象,然后再调用removeStudent方法进行删除。在case 6中,同样是通过循环找到需要修改的学生对象,然后再调用modigyStudentInfo方法进行修改。同时,我们还加入了一些错误处理的代码,以防止用户输入错误的学号。
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