用函数方法编程求1!+2!+....…+n!
时间: 2023-12-01 11:42:12 浏览: 34
以下是两种方法来编程求1!+2!+....…+n!:
1. C语言方法:
```c
#include <stdio.h>
long fun(int n)
{
long sum = 0, i, j, k = 1;
for (i = 1; i <= n; i++)
{
k = 1;
for (j = 1; j <= i; j++)
{
k *= j;
}
sum += k;
}
return sum;
}
int main()
{
int n;
printf("请输入n的值:");
scanf("%d", &n);
printf("%d的阶乘和为:%ld\n", n, fun(n));
return 0;
}
```
2. Python方法:
```python
def factorial(n):
if n == 1:
return 1
else:
return n * factorial(n-1)
def sum_factorial(n):
sum = 0
for i in range(1, n+1):
sum += factorial(i)
return sum
n = int(input("请输入n的值:"))
print("%d的阶乘和为:%d" % (n, sum_factorial(n)))
```