消消乐python代码

消消乐（也称为连连看或匹配3）是一款流行的益智游戏，其基本原理是通过消除同一类型的元素来得分。编写消消乐游戏的Python代码涉及一些图形用户界面设计、算法和数据结构。以下是一个简化的示例，展示了如何用Python和Tkinter库创建一个基本的消消乐游戏框架：

import tkinter as tk
import random

# 创建一个简单的矩阵表示棋盘
def create_board(size):
    return [[random.choice(['O', 'X']) for _ in range(size)] for _ in range(size)]

# 检查行/列是否可以消除
def can_remove(board, x, y):
    return all(board[y][i] == board[y][x] and board[i][x] == board[y][x] for i in range(x, size))

# 实现消除操作
def remove(board, x, y):
    for i in range(x, size):
        if board[y][i] == board[y][x]:
            board[i][x] = ' '
    return board

# 游戏主循环
def main():
    size = 4  # 可以根据需求调整棋盘大小
    board = create_board(size)
    canvas = tk.Canvas(tk.Tk(), width=size * 50, height=size * 50)
    canvas.pack()

    for y in range(size):
        for x in range(size):
            cell = canvas.create_rectangle(x * 50, y * 50, (x + 1) * 50, (y + 1) * 50, fill='black')
            canvas.tag_bind(cell, '<Button-1>', lambda event, x=x, y=y: check_and_remove(event, x, y))

    tk.mainloop()

# 检查点击并尝试消除
def check_and_remove(event, x, y):
    if can_remove(board, x, y):
        board = remove(board, x, y)
        update_canvas(canvas, board)

# 更新画布显示
def update_canvas(canvas, board):
    for y in range(size):
        for x in range(size):
            if board[y][x] == ' ':
                canvas.itemconfig(canvas.find_withtag(f'cell{x}_{y}'), fill='white')
            else:
                canvas.itemconfig(canvas.find_withtag(f'cell{x}_{y}'), fill='black')

if __name__ == '__main__':
    main()