python五子棋源代码

以下是一个简单的 Python 五子棋游戏的源代码示例，仅供参考：

import numpy as np

# 设置棋盘大小
BOARD_SIZE = 15

# 定义棋盘
board = np.zeros((BOARD_SIZE, BOARD_SIZE))


def print_board(board):
    """输出棋盘"""
    print("   ", end="")
    for i in range(BOARD_SIZE):
        print("{:2d}".format(i), end="")
    print()
    for i in range(BOARD_SIZE):
        print("{:2d}".format(i), end="")
        for j in range(BOARD_SIZE):
            if board[i][j] == 1:
                print(" ●", end="")
            elif board[i][j] == 2:
                print(" ○", end="")
            else:
                print(" +", end="")
        print()


def check_win(player, row, col):
    """检查是否胜利"""
    # 水平方向
    count = 1
    for i in range(col - 1, -1, -1):
        if board[row][i] == player:
            count += 1
        else:
            break
    for i in range(col + 1, BOARD_SIZE):
        if board[row][i] == player:
            count += 1
        else:
            break
    if count >= 5:
        return True

    # 垂直方向
    count = 1
    for i in range(row - 1, -1, -1):
        if board[i][col] == player:
            count += 1
        else:
            break
    for i in range(row + 1, BOARD_SIZE):
        if board[i][col] == player:
            count += 1
        else:
            break
    if count >= 5:
        return True

    # 左斜方向
    count = 1
    i, j = row - 1, col - 1
    while i >= 0 and j >= 0:
        if board[i][j] == player:
            count += 1
        else:
            break
        i -= 1
        j -= 1
    i, j = row + 1, col + 1
    while i < BOARD_SIZE and j < BOARD_SIZE:
        if board[i][j] == player:
            count += 1
        else:
            break
        i += 1
        j += 1
    if count >= 5:
        return True

    # 右斜方向
    count = 1
    i, j = row - 1, col + 1
    while i >= 0 and j < BOARD_SIZE:
        if board[i][j] == player:
            count += 1
        else:
            break
        i -= 1
        j += 1
    i, j = row + 1, col - 1
    while i < BOARD_SIZE and j >= 0:
        if board[i][j] == player:
            count += 1
        else:
            break
        i += 1
        j -= 1
    if count >= 5:
        return True

    return False


def play_game():
    """主游戏逻辑"""
    player = 1
    while True:
        print_board(board)
        row = int(input("请玩家{}输入行号：".format(player)))
        col = int(input("请玩家{}输入列号：".format(player)))
        if board[row][col] != 0:
            print("该位置已经有棋子了，请重新输入！")
            continue
        board[row][col] = player
        if check_win(player, row, col):
            print_board(board)
            print("玩家{}获胜！".format(player))
            break
        player = 3 - player  # 切换玩家


if __name__ == "__main__":
    play_game()

该代码使用了 numpy 库来方便地创建和操作二维数组。在 `play_game` 函数中，首先打印棋盘，然后让玩家输入要下的位置，如果该位置已经有棋子了则提示重新输入，否则将该位置的值设置为当前玩家的编号。接着调用 `check_win` 函数检查当前玩家是否胜利，如果是则打印获胜信息并结束游戏，否则切换玩家。`check_win` 函数使用了“连五”算法来判断是否胜利，即检查当前位置的水平、垂直、左斜和右斜方向上是否有连续的五个棋子。注意，这里的玩家编号是 1 和 2，而不是常见的 0 和 1。