nt i =-1; if(i<=0) printf (“****\n”); i=2; else printf (“%%%%\n”);
时间: 2023-12-06 07:45:12 浏览: 25
这段代码存在语法错误,正确的代码如下:
```
int i = -1;
if (i <= 0) {
printf("****\n");
} else {
printf("%%%%\n");
}
i = 2;
```
这段代码的逻辑是:
- 定义一个整型变量 i 并赋值为 -1。
- 如果 i 小于等于 0,则输出 `****`,否则输出 `%%%%`。
- 将 i 的值赋为 2。
相关问题
修改上述OpenGL代码,实现正确的递归调用Vector3f refractionColor(0.0, 0.0, 0.0); if (mtl._transparent) { /*printf("_transparent"); getchar();*/ //折射光,调用递归 Vector3f refractDir; float ni_over_nt; bool refract; if (ray.Direction().dot(closest_hp.normal) < 0) //入射 { ni_over_nt = 1.0 / mtl._refraction; refract = Refract(ray.Direction(), closest_hp.normal, ni_over_nt, refractDir); } else//出射 { ni_over_nt = mtl._refraction; refract = Refract(ray.Direction(), -closest_hp.normal, ni_over_nt, refractDir); } if (refract) { Ray refractRay(closest_hp.position, refractDir); refractRay._origin = closest_hp.position + 1e-2 * refractDir.normalized(); //请把下面代码改掉,填入正确的递归调用 refractionColor = Vector3f(0, 0, 0); //请把上面代码改掉,填入正确的递归调用 } else { refractionColor = Vector3f(0, 0, 0); } //cout << "refractionColor" << refractionColor << endl; } color = color + 0.2 * reflectColor + 0.9 * refractionColor; if (color[0] > 1.0) color[0] = 1.0; if (color[1] > 1.0) color[1] = 1.0; if (color[2] > 1.0) color[2] = 1.0; return color; }
可以添加一个深度限制参数,限制递归的深度,避免无限递归。同时,在递归调用之后,还需要进行颜色的修正,即将递归得到的颜色乘上材质表面的透明度。修改后的代码如下:
Vector3f refractionColor(0.0, 0.0, 0.0);
if (mtl._transparent && depth < MAX_DEPTH)
{
Vector3f refractDir;
float ni_over_nt;
bool refract;
if (ray.Direction().dot(closest_hp.normal) < 0)
{
ni_over_nt = 1.0 / mtl._refraction;
refract = Refract(ray.Direction(), closest_hp.normal, ni_over_nt, refractDir);
}
else
{
ni_over_nt = mtl._refraction;
refract = Refract(ray.Direction(), -closest_hp.normal, ni_over_nt, refractDir);
}
if (refract)
{
Ray refractRay(closest_hp.position, refractDir);
refractRay._origin = closest_hp.position + 1e-2 * refractDir.normalized();
//添加深度限制参数,限制递归的深度
refractionColor = RayColor(refractRay, scene, depth + 1, test, MAX_DEPTH);
//颜色修正,乘上材质表面的透明度
refractionColor = Vector3f(refractionColor[0] * mtl._Kt[0], refractionColor[1] * mtl._Kt[1], refractionColor[2] * mtl._Kt[2]);
}
}
color = color + 0.2 * reflectColor + 0.9 * refractionColor;
if (color[0] > 1.0) color[0] = 1.0;
if (color[1] > 1.0) color[1] = 1.0;
if (color[2] > 1.0) color[2] = 1.0;
return color;
将下面的python代码转成高效的C语言代码 for i in range(N): b, a = signal.butter(4, [6.0/(Cfg['Nt'][k]/2), 50.0/(Cfg['Nt'][k]/2)], 'bandpass') Hin[k][i, :] = signal.lfilter(b, a, Hin[k][i, :])
以下是将Python代码转换为C语言代码的示例:
```c
#include <stdlib.h>
#include <stdio.h>
#include <math.h>
void butter(int N, double Wn[], char* type, double b[], double a[]) {
double c1, c2, c3, c4, c5, c6, c7, c8, c9, c10;
double d1, d2, d3, d4, d5, d6, d7, d8, d9, d10;
double ar1, ar2, ai1, ai2;
double f1, f2, f3, f4, f5, f6, f7, f8, f9, f10;
double p1, p2, p3, p4, p5, p6, p7, p8, p9, p10;
double q1, q2, q3, q4, q5, q6, q7, q8, q9, q10;
double r1, r2, r3, r4, r5, r6, r7, r8, r9, r10;
double s1, s2, s3, s4, s5, s6, s7, s8, s9, s10;
double t1, t2, t3, t4, t5, t6, t7, t8, t9, t10;
double u1, u2, u3, u4, u5, u6, u7, u8, u9, u10;
double v1, v2, v3, v4, v5, v6, v7, v8, v9, v10;
double w1, w2, w3, w4, w5, w6, w7, w8, w9, w10;
double x1, x2, x3, x4, x5, x6, x7, x8, x9, x10;
double y1, y2, y3, y4, y5, y6, y7, y8, y9, y10;
double z1, z2, z3, z4, z5, z6, z7, z8, z9, z10;
double qf1, qf2, qf3, qf4, qf5, qf6, qf7, qf8, qf9, qf10;
double qb1, qb2, qb3, qb4, qb5, qb6, qb7, qb8, qb9, qb10;
double af1, af2, af3, af4, af5, af6, af7, af8, af9, af10;
double ab1, ab2, ab3, ab4, ab5, ab6, ab7, ab8, ab9, ab10;
double a0, a1, a2, a3, a4, b0, b1, b2, b3, b4;
double s, c, alpha, beta, gamma, delta;
double pi = 3.14159265358979323846;
if (strcmp(type, "lowpass") == 0) {
s = sin(pi*Wn[0]);
c = cos(pi*Wn[0]);
alpha = s/(2*N);
beta = sqrt(1 - alpha*alpha);
gamma = (1 - c)/2;
delta = (1 + c)/2;
a0 = delta;
a1 = gamma + beta*I;
a2 = alpha*2 - delta;
a3 = -(gamma + beta*I);
a4 = delta;
b0 = alpha;
b1 = 0;
b2 = -alpha;
b3 = 0;
b4 = alpha;
}
else if (strcmp(type, "highpass") == 0) {
s = sin(pi*Wn[0]);
c = cos(pi*Wn[0]);
alpha = s/(2*N);
beta = sqrt(1 - alpha*alpha);
gamma = (1 + c)/2;
delta = (1 - c)/2;
a0 = delta;
a1 = -(gamma + beta*I);
a2 = alpha*2 - delta;
a3 = gamma + beta*I;
a4 = delta;
b0 = alpha;
b1 = 0;
b2 = -alpha;
b3 = 0;
b4 = alpha;
}
else if (strcmp(type, "bandpass") == 0) {
s = sin(pi*Wn[0]);
c = cos(pi*Wn[0]);
alpha = s*sinh(log(2)/2*N*Wn[1]/s);
beta = sqrt(1 - alpha*alpha);
gamma = c;
delta = 1;
a0 = delta;
a1 = -2*gamma;
a2 = 2*alpha*beta;
a3 = 2*gamma;
a4 = delta;
b0 = alpha;
b1 = 0;
b2 = -alpha;
b3 = 0;
b4 = alpha;
}
else if (strcmp(type, "bandstop") == 0) {
s = sin(pi*Wn[0]);
c = cos(pi*Wn[0]);
alpha = s/sinh(log(2)/2*N*Wn[1]/s);
beta = sqrt(1 - alpha*alpha);
gamma = c;
delta = 1;
a0 = delta;
a1 = -2*gamma;
a2 = 2*alpha*beta;
a3 = 2*gamma;
a4 = delta;
b0 = beta;
b1 = -2*beta*c;
b2 = beta;
b3 = beta;
b4 = -2*beta*c;
}
else {
printf("Invalid filter type.\n");
exit(1);
}
ar1 = a[0];
ar2 = a[1];
ai1 = a[2];
ai2 = a[3];
f1 = b[0];
f2 = b[1];
f3 = b[2];
f4 = b[3];
f5 = b[4];
p1 = 0;
p2 = 0;
p3 = 0;
p4 = 0;
p5 = 0;
q1 = 0;
q2 = 0;
q3 = 0;
q4 = 0;
q5 = 0;
r1 = 0;
r2 = 0;
r3 = 0;
r4 = 0;
r5 = 0;
s1 = 0;
s2 = 0;
s3 = 0;
s4 = 0;
s5 = 0;
t1 = 0;
t2 = 0;
t3 = 0;
t4 = 0;
t5 = 0;
u1 = 0;
u2 = 0;
u3 = 0;
u4 = 0;
u5 = 0;
v1 = 0;
v2 = 0;
v3 = 0;
v4 = 0;
v5 = 0;
w1 = 0;
w2 = 0;
w3 = 0;
w4 = 0;
w5 = 0;
x1 = 0;
x2 = 0;
x3 = 0;
x4 = 0;
x5 = 0;
y1 = 0;
y2 = 0;
y3 = 0;
y4 = 0;
y5 = 0;
z1 = 0;
z2 = 0;
z3 = 0;
z4 = 0;
z5 = 0;
qf1 = 0;
qf2 = 0;
qf3 = 0;
qf4 = 0;
qf5 = 0;
qb1 = 0;
qb2 = 0;
qb3 = 0;
qb4 = 0;
qb5 = 0;
af1 = 0;
af2 = 0;
af3 = 0;
af4 = 0;
af5 = 0;
ab1 = 0;
ab2 = 0;
ab3 = 0;
ab4 = 0;
ab5 = 0;
for (int i = 0; i < N; i++) {
qf5 = qf4;
qf4 = qf3;
qf3 = qf2;
qf2 = qf1;
qf1 = Hin[k][i];
qb5 = qb4;
qb4 = qb3;
qb3 = qb2;
qb2 = qb1;
qb1 = qf5*a0 + qf4*a1 + qf3*a2 + qf2*a3 + qf1*a4 + qb5*b0 + qb4*b1 + qb3*b2 + qb2*b3 + qb1*b4;
af5 = af4;
af4 = af3;
af3 = af2;
af2 = af1;
af1 = qb5*f1 + qb4*f2 + qb3*f3 + qb2*f4 + qb1*f5;
ab5 = ab4;
ab4 = ab3;
ab3 = ab2;
ab2 = ab1;
ab1 = qb5*f1 + qb4*f4 + qb3*f3 + qb2*f2 + qb1*f5;
Hin[k][i] = af1 - ab1;
}
}
```
然后,您可以使用以下代码调用上面的函数:
```c
int main() {
double Wn[] = {6.0/(Cfg['Nt'][k]/2), 50.0/(Cfg['Nt'][k]/2)};
double b[5], a[5];
int N = ...; // 请用您的代码替换此处的 N
butter(4, Wn, "bandpass", b, a);
return 0;
}
```
相关推荐
![7z](https://img-home.csdnimg.cn/images/20210720083312.png)
![zip](https://img-home.csdnimg.cn/images/20210720083736.png)
![pdf](https://img-home.csdnimg.cn/images/20210720083512.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)
![](https://csdnimg.cn/download_wenku/file_type_ask_c1.png)