二叉树的基本操作功能
时间: 2024-03-01 12:46:35 浏览: 23
以下是二叉树的基本操作功能的介绍和演示:
1. 建立二叉树:根据输入的数据建立一个二叉树。
```python
class TreeNode:
def __init__(self, val=0, left=None, right=None):
self.val = val
self.left = left
self.right = right
def createBinaryTree(data):
if not data:
return None
val = data.pop(0)
if val == '#':
return None
node = TreeNode(val)
node.left = createBinaryTree(data)
node.right = createBinaryTree(data)
return node
data = ['A', 'B', 'D', '#', 'G', '#', '#', 'E', 'H', '#', '#', '#', 'C', 'F', '#', '#', 'I', 'K', '#', '#', '#']
root = createBinaryTree(data)
```
2. 前序遍历:按照根节点、左子树、右子树的顺序遍历二叉树。
```python
def preorderTraversal(root):
if not root:
return []
stack = [root]
res = []
while stack:
node = stack.pop()
res.append(node.val)
if node.right:
stack.append(node.right)
if node.left:
stack.append(node.left)
return res
preorder = preorderTraversal(root)
print("前序遍历结果:", preorder)
```
3. 中序遍历:按照左子树、根节点、右子树的顺序遍历二叉树。
```python
def inorderTraversal(root):
if not root:
return []
stack = []
res = []
node = root
while stack or node:
while node:
stack.append(node)
node = node.left
node = stack.pop()
res.append(node.val)
node = node.right
return res
inorder = inorderTraversal(root)
print("中序遍历结果:", inorder)
```
4. 后序遍历:按照左子树、右子树、根节点的顺序遍历二叉树。
```python
def postorderTraversal(root):
if not root:
return []
stack = [root]
res = []
while stack:
node = stack.pop()
res.append(node.val)
if node.left:
stack.append(node.left)
if node.right:
stack.append(node.right)
return res[::-1]
postorder = postorderTraversal(root)
print("后序遍历结果:", postorder)
```
5. 统计节点个数:采用递归的方式统计二叉树的节点个数。
```python
def countNodes(root):
if not root:
return 0
return 1 + countNodes(root.left) + countNodes(root.right)
count = countNodes(root)
print("二叉树的节点个数:", count)
```
6. 统计度为1的节点个数:采用递归的方式统计二叉树的度为1的节点个数。
```python
def countDegreeOneNodes(root):
if not root:
return 0
if (root.left and not root.right) or (not root.left and root.right):
return 1 + countDegreeOneNodes(root.left) + countDegreeOneNodes(root.right)
else:
return countDegreeOneNodes(root.left) + countDegreeOneNodes(root.right)
countDegreeOne = countDegreeOneNodes(root)
print("二叉树的度为1的节点个数:", countDegreeOne)
```
7. 统计叶子节点个数:采用递归的方式统计二叉树的叶子节点个数。
```python
def countLeafNodes(root):
if not root:
return 0
if not root.left and not root.right:
return 1
return countLeafNodes(root.left) + countLeafNodes(root.right)
countLeaf = countLeafNodes(root)
print("二叉树的叶子节点个数:", countLeaf)
```
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