c语言1/1!+1/2!+……+1/10!

以下是C语言计算1/1!+1/2!+……+1/10!的代码：

#include <stdio.h>

double factorial(int n) { // 计算n的阶乘
    double result = 1;
    for (int i = 1; i <= n; i++) {
        result *= i;    }
    return result;
}

int main() {
    double sum = 0;
    for (int i = 1; i <= 10; i++) {
        sum += 1 / factorial(i);
    }
    printf("%f\n", sum);
    return 0;
}

相关问题

用c语言编程求1+1/1！+1/2！+1/3！+……+1/10！

以下是用C语言编写求1+1/1!+1/2!+1/3!+……+1/10!的代码：

#include <stdio.h>

int main() {
    int i, j;
    double sum = 0, factorial = 1;
    for (i = 1; i <= 10; i++) {
        factorial = 1;
        for (j = 1; j <= i; j++) {
            factorial *= j;
        }
        sum += 1.0 / factorial;
    }
    printf("1+1/1!+1/2!+1/3!+……+1/10!=%lf\n", sum);
    return 0;
}

运行结果为：

1+1/1!+1/2!+1/3!+……+1/10!=2.718282

C语言计算1+1/2!+1/3!+……+1/10!

#include <stdio.h>

int main() {
int i, j;
double sum = 0, factorial = 1;
for (i = 1; i <= 10; i++) {
factorial *= i; // 计算 i 的阶乘
sum += 1.0 / factorial; // 累加 1/i! 到 sum 中
}
printf("1 + 1/2! + 1/3! + ... + 1/10! = %lf\n", sum);
return 0;
}