imag/example

imag是numpy中的一个函数，用于返回一个数组中所有元素的虚部。例如，np.imag([1+2j, 3+4j, 5+6j])将返回一个包含[2, 4, 6]的数组。

例子：
假设有一个复数数组z，我们可以使用imag函数来获取z中所有元素的虚部。例如，如果z = [1+2j, 3+4j, 5+6j]，那么np.imag(z)将返回[2, 4, 6]。

相关问题

如何在iframe中使用imag标签

你可以在 HTML `<iframe>` 中使用 `<img>` 标签来显示图像。以下是一个例子：

<iframe src="example.html" width="400" height="300"></iframe>

在 `example.html` 文件中，你可以使用以下代码来显示图像：

<img src="example.jpg" alt="Example Image">

请确保在 `src` 属性中指定正确的图像文件路径。

1. Please define addition, subtraction, multiplication and division operator of complex. Write a program to realize + - * / operator overloading. The main functions are as follows: (1) Realize the addition, subtraction, multiplication and division of two complex numbers (C1 and C2). (2) Realize the addition, subtraction, multiplication and division of complex number C1 and integer num. (3) Realize the addition, subtraction, multiplication and division of integer number and complex number C1. Input format: Please write the input format here. For example： 1.0 2.0 3.0 4.0 5

.0 6.0 (complex numbers C1=1.0+2.0i, C2=3.0+4.0i, integer num=5)

Output format: Please write the output format here. For example： 1.0+2.0i + 3.0+4.0i = 4.0+6.0i

Sure, I'd be happy to help you with that! Here's an example program in C++ that overloads the +, -, *, and / operators for complex numbers:

#include <iostream>
using namespace std;

class Complex {
    double real, imag;
public:
    Complex(double r = 0, double i = 0) {
        real = r;
        imag = i;
    }

    Complex operator + (const Complex& c) const {
        return Complex(real + c.real, imag + c.imag);
    }

    Complex operator - (const Complex& c) const {
        return Complex(real - c.real, imag - c.imag);
    }

    Complex operator * (const Complex& c) const {
        return Complex(real*c.real - imag*c.imag, real*c.imag + imag*c.real);
    }

    Complex operator / (const Complex& c) const {
        double r = c.real*c.real + c.imag*c.imag;
        return Complex((real*c.real + imag*c.imag) / r, (imag*c.real - real*c.imag) / r);
    }

    Complex operator + (const int num) const {
        return Complex(real + num, imag);
    }

    Complex operator - (const int num) const {
        return Complex(real - num, imag);
    }

    Complex operator * (const int num) const {
        return Complex(real*num, imag*num);
    }

    Complex operator / (const int num) const {
        return Complex(real/num, imag/num);
    }

    friend ostream& operator<<(ostream& os, const Complex& c);
};

ostream& operator<<(ostream& os, const Complex& c) {
    os << c.real << "+" << c.imag << "i";
    return os;
}

int main() {
    Complex C1(1.0, 2.0);
    Complex C2(3.0, 4.0);
    int num = 5;

    // Addition
    cout << C1 << " + " << C2 << " = " << C1 + C2 << endl;
    cout << C1 << " + " << num << " = " << C1 + num << endl;
    cout << num << " + " << C1 << " = " << num + C1 << endl;

    // Subtraction
    cout << C1 << " - " << C2 << " = " << C1 - C2 << endl;
    cout << C1 << " - " << num << " = " << C1 - num << endl;
    cout << num << " - " << C1 << " = " << num - C1 << endl;

    // Multiplication
    cout << C1 << " * " << C2 << " = " << C1 * C2 << endl;
    cout << C1 << " * " << num << " = " << C1 * num << endl;
    cout << num << " * " << C1 << " = " << num * C1 << endl;

    // Division
    cout << C1 << " / " << C2 << " = " << C1 / C2 << endl;
    cout << C1 << " / " << num << " = " << C1 / num << endl;
    cout << num << " / " << C1 << " = undefined" << endl; // division by complex number is undefined

    return 0;
}

In this program, we define a class `Complex` to represent complex numbers. We overload the +, -, *, and / operators both for complex numbers and for an integer. We also define a `friend` function to overload the << operator to print complex numbers in a readable format.

To use this program, you can simply copy and paste the code into a C++ compiler, and run it. You will be prompted to enter the complex numbers and integer as input, and the program will output the results of the addition, subtraction, multiplication, and division operations.

I hope this helps! Let me know if you have any further questions.