一个含有字符串的数组，例如:["a","b","a","c","b","d","a"],需要得到一个新数组 ["a1","b1","a2","c","b2","d","a3"] c#

你可以通过遍历原数组，并使用 Dictionary 来统计每个字符串出现的次数，然后再次遍历原数组，根据每个字符串出现的次数，构造新的字符串数组。以下是一个示例代码：

string[] originalArray = new string[] { "a", "b", "a", "c", "b", "d", "a" };
Dictionary<string, int> countDict = new Dictionary<string, int>();
string[] newArray = new string[originalArray.Length];

// 统计每个字符串出现的次数
for (int i = 0; i < originalArray.Length; i++)
{
    string str = originalArray[i];
    if (countDict.ContainsKey(str))
    {
        countDict[str]++;
    }
    else
    {
        countDict[str] = 1;
    }

    int count = countDict[str];
    newArray[i] = str + count;
}

// 输出新的字符串数组
foreach (string str in newArray)
{
    Console.Write(str + " ");
}