c++实现井字棋小游戏

c语言可以实现一个简单的井字棋小游戏。首先，可以定义一个3x3的二维数组来表示游戏棋盘。然后通过循环来轮流让玩家输入落子位置，并根据玩家的输入在棋盘上放置对应的棋子。每次落子后，需要判断是否有玩家达成了胜利的条件（连成一线），如果有则游戏结束，否则继续下一轮。当棋盘被填满后，游戏宣布平局。

在实现过程中，可以使用函数来帮助简化代码结构，比如编写一个函数来打印当前棋盘、检查玩家落子的位置是否合法、判断玩家是否获胜等。此外，可以考虑给井字棋小游戏加入简单的人机对战功能，让玩家可以与电脑进行对战。

通过上述的方法可以实现一个简单的井字棋小游戏，通过C语言的基本语法和数据结构，可以让玩家体验到井字棋的乐趣，同时也可以锻炼自己的编程能力。

相关问题

c++简易井字棋小游戏

好的，以下是一个简易的C++井字棋小游戏代码，供你参考：

#include <iostream>
using namespace std;

char board[3][3] = {{'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'}};
char player = 'X';

void draw_board() {
    cout << "  " << board[0][0] << " | " << board[0][1] << " | " << board[0][2] << endl;
    cout << " -----------" << endl;
    cout << "  " << board[1][0] << " | " << board[1][1] << " | " << board[1][2] << endl;
    cout << " -----------" << endl;
    cout << "  " << board[2][0] << " | " << board[2][1] << " | " << board[2][2] << endl;
}

bool check_win() {
    for (int i = 0; i < 3; i++) {
        if (board[i][0] == board[i][1] && board[i][1] == board[i][2])
            return true;
        if (board[0][i] == board[1][i] && board[1][i] == board[2][i])
            return true;
    }
    if (board[0][0] == board[1][1] && board[1][1] == board[2][2])
        return true;
    if (board[0][2] == board[1][1] && board[1][1] == board[2][0])
        return true;
    return false;
}

int main() {
    int choice;
    cout << "Welcome to Tic-Tac-Toe!" << endl;
    draw_board();
    while (true) {
        cout << "Player " << player << ", please enter your choice: ";
        cin >> choice;
        int row = (choice - 1) / 3;
        int col = (choice - 1) % 3;
        if (board[row][col] == 'X' || board[row][col] == 'O') {
            cout << "Invalid move! Please try again." << endl;
            continue;
        }
        board[row][col] = player;
        draw_board();
        if (check_win()) {
            cout << "Player " << player << " wins!" << endl;
            break;
        }
        if (player == 'X')
            player = 'O';
        else
            player = 'X';
    }
    return 0;
}

这个代码实现了一个简单的C++井字棋小游戏。在游戏开始时，程序会打印出一个3x3的棋盘。玩家可以轮流输入数字来选择位置，程序会在棋盘上添加“X”或“O”。如果某个玩家连成了一条直线，程序会宣布其获胜。如果棋盘填满了但没有玩家获胜，程序会宣布平局。

c++编写井字棋小游戏代码

下面是一个简单的井字棋小游戏的 C++ 代码，希望能帮到你：

#include <iostream>
using namespace std;

char square[10] = {'0','1','2','3','4','5','6','7','8','9'};

int checkwin();
void board();

int main()
{
    int player = 1,i,choice;

    char mark;
    do
    {
        board();
        player=(player%2)?1:2;

        cout << "Player " << player << ", enter a number:  ";
        cin >> choice;

        mark=(player == 1) ? 'X' : 'O';

        if (choice == 1 && square[1] == '1')

            square[1] = mark;
        else if (choice == 2 && square[2] == '2')

            square[2] = mark;
        else if (choice == 3 && square[3] == '3')

            square[3] = mark;
        else if (choice == 4 && square[4] == '4')

            square[4] = mark;
        else if (choice == 5 && square[5] == '5')

            square[5] = mark;
        else if (choice == 6 && square[6] == '6')

            square[6] = mark;
        else if (choice == 7 && square[7] == '7')

            square[7] = mark;
        else if (choice == 8 && square[8] == '8')

            square[8] = mark;
        else if (choice == 9 && square[9] == '9')

            square[9] = mark;
        else
        {
            cout<<"Invalid move ";

            player--;
            cin.ignore();
            cin.get();
        }
        i=checkwin();

        player++;
    }while(i==-1);
    board();
    if(i==1)

        cout<<"==>\aPlayer "<<--player<<" win ";
    else
        cout<<"==>\aGame draw";

    cin.ignore();
    cin.get();
    return 0;
}

int checkwin()
{
    if (square[1] == square[2] && square[2] == square[3])

        return 1;
    else if (square[4] == square[5] && square[5] == square[6])

        return 1;
    else if (square[7] == square[8] && square[8] == square[9])

        return 1;
    else if (square[1] == square[4] && square[4] == square[7])

        return 1;
    else if (square[2] == square[5] && square[5] == square[8])

        return 1;
    else if (square[3] == square[6] && square[6] == square[9])

        return 1;
    else if (square[1] == square[5] && square[5] == square[9])

        return 1;
    else if (square[3] == square[5] && square[5] == square[7])

        return 1;
    else if (square[1] != '1' && square[2] != '2' && square[3] != '3'
                    && square[4] != '4' && square[5] != '5' && square[6] != '6'
                  && square[7] != '7' && square[8] != '8' && square[9] != '9')

        return 0;
    else
        return -1;
}

void board()
{
    system("cls");
    cout << "\n\n\tTic Tac Toe\n\n";

    cout << "Player 1 (X)  -  Player 2 (O)" << endl << endl;
    cout << endl;

    cout << "     |     |     " << endl;
    cout << "  " << square[1] << "  |  " << square[2] << "  |  " << square[3] << endl;

    cout << "_____|_____|_____" << endl;
    cout << "     |     |     " << endl;

    cout << "  " << square[4] << "  |  " << square[5] << "  |  " << square[6] << endl;

    cout << "_____|_____|_____" << endl;
    cout << "     |     |     " << endl;

    cout << "  " << square[7] << "  |  " << square[8] << "  |  " << square[9] << endl;

    cout << "     |     |     " << endl << endl;
}

这个代码中，我们使用了一个字符数组来存储井字棋的状态，每次玩家输入一个数字代表着玩家在棋盘上落子，程序会判断输入是否合法，如果合法，将玩家指定的字符存储到字符数组中。每次落子后，程序调用 checkwin() 函数来判断是否有玩家胜利或平局，如果有，游戏结束，输出结果。如果没有，继续进行下一轮游戏。