Write a recursive function that will output all the subsets of a set of n elements (withoutrepeating any subsets)
时间: 2023-05-19 12:02:20 浏览: 78
以下是一个递归函数,它可以输出一个n个元素集合的所有子集(不重复任何子集):
```
void generateSubsets(vector<int>& nums, vector<int>& subset, vector<vector<int>>& result, int start) {
result.push_back(subset);
for (int i = start; i < nums.size(); i++) {
subset.push_back(nums[i]);
generateSubsets(nums, subset, result, i + 1);
subset.pop_back();
}
}
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> result;
vector<int> subset;
generateSubsets(nums, subset, result, 0);
return result;
}
```
这个函数使用了递归来生成所有的子集。我们从空集开始,然后依次将每个元素添加到子集中,生成新的子集。对于每个新的子集,我们都将其添加到结果集中。最后,我们得到了所有的子集。
相关问题
Write a recursive function that prints the binary equivalent of an integer in C program
Here is an example C program that uses a recursive function to print the binary equivalent of an integer:
```c
#include <stdio.h>
void toBinary(int num);
int main() {
int decimal;
printf("Enter a decimal number: ");
scanf("%d", &decimal);
printf("Binary equivalent: ");
toBinary(decimal);
return 0;
}
void toBinary(int num) {
if (num <= 1) {
printf("%d", num);
return;
}
toBinary(num / 2);
printf("%d", num % 2);
}
```
In this code, the `toBinary()` function is called recursively to print the binary equivalent of the input decimal number. The function takes an integer `num` as input and recursively divides it by 2 until it reaches 1 or 0. At each step, the remainder of the division is printed in reverse order, giving the binary equivalent of the original number.
Write a program to print all digits of a given number by using a recursive function.
Here's the Python code to print all digits of a given number using a recursive function:
```
def print_digits(n):
if n < 10:
print(n)
else:
print_digits(n // 10)
print(n % 10)
# Example usage:
print_digits(12345) # Output: 1 2 3 4 5
```
In this code, the `print_digits` function takes an integer `n` as input. If `n` is less than 10, we simply print it. Otherwise, we first call the `print_digits` function recursively with `n // 10`, which gives us all the digits except for the last one. Then, we print the last digit by computing `n % 10`. This way, we print the digits in reverse order (from right to left).
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