#include<iostream> using namespace std; #include<string> class Employee { friend ostream& operator<<(ostream& out, Employee& employee); private: string name; int id; double salary; public: Employee(string n, int i, double s):name(n), id(i), salary(s) {}; void setname(string n) { name = n; } void setid(int i) { id = i; } void setsalary(double s) { salary = s; } string getname() { return name; } int getid() { return id; } double getsalary() { return salary; } }; ostream& operator<<(ostream& cout, Employee& employee) { cout << "姓名为" << employee.getname() << endl; cout << "id为" << employee.getid() << endl; cout << "薪水是" << employee.getsalary() << endl; }; int main() { Employee employee("潘仁飞", 15.150); system("pause"); return 0; }哪里有问题

代码中有两处问题：

1.在 `Employee` 类的构造函数中，只传入了两个参数 `"潘仁飞"` 和 `15.15`，然而该构造函数需要三个参数，分别是 `name`、`id` 和 `salary`。因此需要将构造函数中的参数数量改为三个，比如改为 `Employee(string n, int i, double s)`。

2.在 `main` 函数中，没有调用 `operator<<` 函数来输出 `employee` 对象的信息。需要在 `main` 函数中添加如下代码：`cout << employee;`。

修改后的代码如下：

#include<iostream> 
#include<string> 

using namespace std; 

class Employee { 
	friend ostream& operator<<(ostream& out, Employee& employee); 
private: 
	string name; 
	int id; 
	double salary; 
public: 
	Employee(string n, int i, double s):name(n), id(i), salary(s) {}; 
	void setname(string n) 
	{ 
		name = n; 
	} 
	void setid(int i) 
	{ 
		id = i; 
	} 
	void setsalary(double s) 
	{ 
		salary = s; 
	} 
	string getname() 
	{ 
		return name; 
	} 
	int getid() 
	{ 
		return id; 
	} 
	double getsalary() 
	{ 
		return salary; 
	} 
}; 

ostream& operator<<(ostream& cout, Employee& employee) { 
	cout << "姓名为" << employee.getname() << endl; 
	cout << "id为" << employee.getid() << endl; 
	cout << "薪水是" << employee.getsalary() << endl; 
}; 

int main() { 
	Employee employee("潘仁飞", 1, 15.15); 
	cout << employee; 
	system("pause"); 
	return 0; 
}