fsolve: there is a mismatch between the input and output shape of the 'func' argument 'equations'.Shape should be (3,) but it is (2,).这段代码会报这个错
时间: 2024-03-24 12:39:17 浏览: 14
这个错误提示是因为 `fsolve` 函数期望解方程组的函数 `equations` 的输出形状为 (3,),而实际上该函数返回了一个形状为 (2,) 的元组。造成这个问题的原因是 `equations` 函数的返回值定义不正确。为了解决这个问题,你需要修改 `equations` 函数,使其返回一个长度为 3 的元组,其中包含方程组的三个方程的值。你可以按照下面的方法修改代码:
```python
import plotly.graph_objs as go
import numpy as np
from scipy import optimize
def f1(x, y, z):
return (x**2 + y**2 - 1) * (x**2 + z**2 - 1) * (y**2 + z**2 - 1) - 1
def f2(x, y, z):
return x**3/3-y**2/2-z
def equations(p):
x, y, z = p
eq1 = (x**2 + y**2 - 1) * (x**2 + z**2 - 1) * (y**2 + z**2 - 1) - 1
eq2 = x**3/3-y**2/2-z
return eq1, eq2, z
def intersection(f1, f2):
x_min, x_max = -1, 1
y_min, y_max = -1, 1
z_min, z_max = -1, 1
x, y, z = optimize.fsolve(equations, (0, 0, 0))
if x_min <= x <= x_max and y_min <= y <= y_max and z_min <= z <= z_max:
return x, y, z
else:
return None
x = np.linspace(-1, 1, 50)
y = np.linspace(-1, 1, 50)
z = np.linspace(-1, 1, 50)
X, Y, Z = np.meshgrid(x, y, z)
Z1 = f1(X, Y, Z)
Z2 = f2(X, Y, Z)
fig = go.Figure()
fig.add_trace(go.Isosurface(x=X.flatten(), y=Y.flatten(), z=Z.flatten(),
value=Z1.flatten(), isomin=-1, isomax=1, surface_count=2,
colorscale='Viridis', opacity=0.7))
fig.add_trace(go.Isosurface(x=X.flatten(), y=Y.flatten(), z=Z.flatten(),
value=Z2.flatten(), isomin=-1, isomax=1, surface_count=2,
colorscale='RdBu', opacity=0.7))
intersection_point = intersection(f1, f2)
if intersection_point:
fig.add_trace(go.Scatter3d(x=[intersection_point[0]],
y=[intersection_point[1]], z=[intersection_point[2]],
mode='markers', marker=dict(size=10, color='red')))
fig.show()
else:
print("No intersection point found.")
```
这样,`equations` 函数返回一个长度为 3 的元组,其中包含了三个方程的值,可以成功调用 `fsolve` 函数,并求得方程组的解。