用lammps写一个代码要求生成一个晶向为x[110] y[-111] z[1-12],xyz方向长度为100 100 100的预置位错的Ni原子模型
时间: 2024-09-13 07:07:37 浏览: 42
lindemann:lindemann是一个python软件包,用于计算lammps轨迹的Lindemann指数
在LAMMPS (Large-scale Atomic/Molecular Massively Parallel Simulator) 中,创建一个预置位错模型需要使用特定的单元格结构和原子坐标。对于指定的晶向x[110] y[-111] z[1-12],你需要使用Miller指数来描述,而这个晶向并不直接对应标准的立方晶系,所以可能需要做一些假设或转换。以下是一个基本的示例代码,假设你正在处理的是一个立方晶系的Ni(镍)晶体,我们将从标准的体心立方晶格开始,并通过修改原子坐标来引入位错。
```lammps
# Include necessary LAMMPS potentials
#include "pair_style eam/ni"
units metal
dimension 3
# Define the lattice constant for Ni
lattice cubic a 3.52 # 3.52 Å is the typical Ni lattice parameter
# Create a box with dimensions of x=100, y=100, z=100
region box block -50 50 -50 50 -50 50
create_box 0 box
# Set up the atom types and masses (Ni default in EAM potential)
mass Ni Ni
# Initialize all atoms as Ni at the center of the box
reset_timestep 0
atom_style atomic
set num_atoms 0
# Generate a FCC lattice
foreach i [-50:50] {
foreach j [-50:50] {
foreach k [-50:50] {
if (i == 0 && j == 0 && k == 0) continue
position i*a j*a k*a Ni
}
}
}
# Now, introduce the pre-defined [110] <1-11> crystallographic direction
# This is an approximation since it's not standard Miller indices
# Let's assume we want to place the dislocation along x-direction shifted by half the lattice vector
dislocation_position = 0.5 * a
for (i = 0; i <= 99; i++) {
# Shift every other row along x-direction
if (i % 2 == 0) {
# Along [110]
newpos[i+1][j][k] = [i+1]*a[j]*a[k] + dislocation_position
} else {
newpos[i][j][k] = i*a[j]*k*a + dislocation_position
}
}
# Update atom positions
fix 1 all set pos newpos
# Run a short equilibration step
timestep 1
minimize 1e-8 1e-10 1000 force
```
请注意,这个代码只是一个基本的示例,实际应用中可能需要调整细节,特别是位错线的精确放置可能会更复杂。此外,预置位错的生成往往需要考虑位错线的完整周期性和边界条件的影响。
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