用Python写一段能对一个数进行因式分解的代码
时间: 2024-04-29 16:24:58 浏览: 14
Sure, I can help you with that! Here's a Python code that can factorize a given integer:
```python
def factorize(num):
factors = []
i = 2
while i <= num:
if num % i == 0:
factors.append(i)
num //= i
else:
i += 1
return factors
# Example usage:
num = 1234567890
print(f"Factors of {num}: {factorize(num)}")
```
This code uses a simple algorithm to find prime factors of a given number. It starts with 2 and divides the number by it as long as it's divisible, then moves on to 3, 4, and so on until the number is fully factorized.
I hope this helps! Let me know if you have any other questions.
相关问题
用 python 编写一个程序.输入 小于 1000 的数.进行因式分解
好的,我可以帮您编写一个因式分解的程序。以下是 Python 代码:
```python
n = int(input("请输入一个小于1000的数:"))
i = 2
while i <= n:
if n % i == 0:
n = int(n / i)
print(i)
else:
i += 1
```
您可以直接复制代码并运行,然后输入一个小于1000的正整数,程序会输出其因式分解的结果。如果您有其他问题需要咨询,可以随时问我哦。
写出一个因式分解的代码
以下是一个简单的因式分解代码,可以分解任意正整数:
#include <stdio.h>
int main() {
int n, i;
printf("请输入一个正整数:");
scanf("%d", &n);
printf("%d = ", n);
for (i = 2; i <= n; i++) {
while (n % i == 0) {
printf("%d", i);
n /= i;
if (n != 1) {
printf(" * ");
}
}
}
printf("\n");
return 0;
}
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