1 class A 2 { 3 final int f=10; 4 double d; 5 abstract void method(); 6 }
时间: 2024-03-25 17:36:07 浏览: 50
这段代码定义了一个抽象类A,包含一个final修饰的int类型变量f、一个double类型变量d和一个抽象方法method()。final修饰的变量f表示该变量的值不能被修改,因此在类A中定义时必须进行初始化。
需要注意的是,抽象类中的抽象方法没有具体的实现,因此不能直接创建抽象类的实例。如果要使用抽象类中的方法,必须通过继承该抽象类并实现其中的抽象方法来创建一个子类。例如:
```
abstract class A {
final int f = 10;
double d;
abstract void method();
}
class B extends A {
void method() {
System.out.println("This is a method in B");
}
}
public class E {
public static void main(String args[]) {
A a = new B();
a.method(); // 输出"This is a method in B"
}
}
```
在这个例子中,B类继承了A类,并实现了其中的抽象方法method()。在主函数中,创建了一个B类的实例并将其向上转型为A类型,通过A类型的变量来调用method()方法,输出了一段信息。
相关问题
把public abstract class Employee { protected String name; // 姓名 protected double fixedSalary; // 固定工资 public Employee(String name, double fixedSalary) { this.name = name; this.fixedSalary = fixedSalary; } // 计算月工资的抽象方法 public abstract double calculateSalary(int overtime);}和public class SeniorEngineer extends Employee { private static final double OVERTIME_SUBSIDY = 50.0; public SeniorEngineer(String name) { super(name, 5000.0); } @Override public double calculateSalary(int overtime) { return fixedSalary + overtime * OVERTIME_SUBSIDY; }}public class JuniorEngineer extends Employee { private static final double OVERTIME_SUBSIDY = 30.0; public JuniorEngineer(String name) { super(name, 3000.0); } @Override public double calculateSalary(int overtime) { return fixedSalary + overtime * OVERTIME_SUBSIDY; }}public class Trainee extends Employee { private static final double OVERTIME_SUBSIDY = 20.0; public Trainee(String name) { super(name, 2000.0); } @Override public double calculateSalary(int overtime) { return fixedSalary + overtime * OVERTIME_SUBSIDY; }}和public class Main { public static void main(String[] args) { Employee[] employees = { new SeniorEngineer("张三"), new JuniorEngineer("李四"), new Trainee("王五") }; int[] overtimes = {10, 20, 30}; for (int i = 0; i < employees.length; i++) { double salary = employees[i].calculateSalary(overtimes[i]); System.out.println(String.format("%s的月工资为:%.2f元", employees[i].name, salary)); } }}合成一个程序
public abstract class Employee {
protected String name; // 姓名
protected double fixedSalary; // 固定工资
public Employee(String name, double fixedSalary) {
this.name = name;
this.fixedSalary = fixedSalary;
}
// 计算月工资的抽象方法
public abstract double calculateSalary(int overtime);
}
public class SeniorEngineer extends Employee {
private static final double OVERTIME_SUBSIDY = 50.0;
public SeniorEngineer(String name) {
super(name, 5000.0);
}
@Override
public double calculateSalary(int overtime) {
return fixedSalary + overtime * OVERTIME_SUBSIDY;
}
}
public class JuniorEngineer extends Employee {
private static final double OVERTIME_SUBSIDY = 30.0;
public JuniorEngineer(String name) {
super(name, 3000.0);
}
@Override
public double calculateSalary(int overtime) {
return fixedSalary + overtime * OVERTIME_SUBSIDY;
}
}
public class Trainee extends Employee {
private static final double OVERTIME_SUBSIDY = 20.0;
public Trainee(String name) {
super(name, 2000.0);
}
@Override
public double calculateSalary(int overtime) {
return fixedSalary + overtime * OVERTIME_SUBSIDY;
}
}
public class Main {
public static void main(String[] args) {
Employee[] employees = {
new SeniorEngineer("张三"),
new JuniorEngineer("李四"),
new Trainee("王五")
};
int[] overtimes = {10, 20, 30};
for (int i = 0; i < employees.length; i++) {
double salary = employees[i].calculateSalary(overtimes[i]);
System.out.println(String.format("%s的月工资为:%.2f元", employees[i].name, salary));
}
}
}
JAVA 定义容器Container接口。模拟实现一个容器类层次结构,并进行接口的实现、抽象方法重写和多态机制测试。各容器类实现求面积、周长的方法。 1.定义接口Container: 属性: public static final double pi=3.14 ; 抽象方法: public abstract double area(); public abstract double perimeter(); static double sumofArea(Container c[]); static double sumofPerimeter(Container c[]); 其中两个静态方法分别计算返回容器数组中所有对象的面积之和、周长之和; 2.定义Rectangle类、Circle类均实现自Container接口。 Rectangel类(属性:长,宽double类型)、Circle类(属性:半径,double类型)。 输入格式: 第一行n表示对象个数,对象类型用Rectangle、Circle区分,Rectangle表示长方形对象,后面输入长,宽,输入Circle表示圆对象,后面是输入半径。 输出格式: 分别输出所有容器对象的面积之和、周长之和,结果保留小数点后2位。 输入样例: 在这里给出一组输入。例如: 4 Circle 15.7 Rectangle 23.5 100 Circle 46.8 Rectangle 17.5 200 输出样例: 在这里给出相应的输出。例如: 周长之和:56771.13 面积之和:472290.12
好的,我了解了你的问题,下面是代码示例:
首先是 Container 接口的定义:
public interface Container {
public static final double pi = 3.14;
public abstract double area();
public abstract double perimeter();
public static double sumofArea(Container c[]) {
double sum = 0;
for(Container container : c) {
sum += container.area();
}
return sum;
}
public static double sumofPerimeter(Container c[]) {
double sum = 0;
for(Container container : c) {
sum += container.perimeter();
}
return sum;
}
}
然后是 Rectangle 类的实现:
public class Rectangle implements Container {
private double length;
private double width;
public Rectangle(double length, double width) {
this.length = length;
this.width = width;
}
@Override
public double area() {
return length * width;
}
@Override
public double perimeter() {
return 2 * (length + width);
}
}
最后是 Circle 类的实现:
public class Circle implements Container {
private double radius;
public Circle(double radius) {
this.radius = radius;
}
@Override
public double area() {
return pi * radius * radius;
}
@Override
public double perimeter() {
return 2 * pi * radius;
}
}
主函数部分:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
Container[] containers = new Container[n];
for(int i = 0; i < n; i++) {
String type = sc.next();
if(type.equals("Rectangle")) {
double length = sc.nextDouble();
double width = sc.nextDouble();
containers[i] = new Rectangle(length, width);
}
else if(type.equals("Circle")) {
double radius = sc.nextDouble();
containers[i] = new Circle(radius);
}
}
System.out.println("周长之和:" + String.format("%.2f", Container.sumofPerimeter(containers)));
System.out.println("面积之和:" + String.format("%.2f", Container.sumofArea(containers)));
}
}
注释:
主函数通过 Scanner 类从控制台输入对象个数和每个对象的类型和属性,并使用 switch 语句实例化不同的对象,最后调用接口的静态方法输出面积和周长之和。在输出时,使用 String.format("%.2f", num) 格式化输出结果,保留两位小数。
希望这份代码能够解决你的问题,注意不要泄露你的要求哦。
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