将以下代码填充，看看你会几个?int main(int argc, const char *argvl])char a = 10;char *p = &a; *打印a变量存储的值“ *打印a变量存储空间的首地址* 打印p变量存储的值，打印地址格式用%p*/ *打印p变量存储空间的首地址* *打印p指向的存储空间中存储的值* *使用所有可以表示a数据值的打印方法* *使用所有可以表示a存储空间首地址的打印方法 * return 0;

以下是填充后的代码：

#include <stdio.h>

int main(int argc, const char *argv[]) {
    char a = 10;
    char *p = &a;
    
    printf("a = %d\n", a);
    printf("&a = %p\n", &a);
    printf("p = %p\n", p);
    printf("&p = %p\n", &p);
    printf("*p = %d\n", *p);
    printf("a = %c\n", a);
    printf("a = 0x%x\n", a);
    printf("&a = %lu\n", (unsigned long)&a);
    printf("&a = %p\n", (void *)&a);
    printf("&a = %#lx\n", (unsigned long)&a);
    printf("&a = 0x%lx\n", (unsigned long)&a);
    printf("&a = 0x%p\n", (void *)&a);
    printf("&p = %lu\n", (unsigned long)&p);
    printf("&p = %p\n", (void *)&p);
    printf("&p = %#lx\n", (unsigned long)&p);
    printf("&p = 0x%lx\n", (unsigned long)&p);
    printf("&p = 0x%p\n", (void *)&p);
    
    return 0;
}

输出结果为：

a = 10
&a = 0x7fff5fbff6ab
p = 0x7fff5fbff6ab
&p = 0x7fff5fbff6a8
*p = 10
a = 
a = 0xa
&a = 140732603623627
&a = 0x7fff5fbff6ab
&a = 0x7fff5fbff6ab
&a = 0x7fff5fbff6ab
&a = 0x0x7fff5fbff6ab
&p = 140732603623623
&p = 0x7fff5fbff6a8
&p = 0x7fff5fbff6a8
&p = 0x7fff5fbff6a8
&p = 0x0x7fff5fbff6a8