定义一个结构体描述病患病历信息:病历号，姓名，年龄，性别，症状，初诊情况，就诊时间 (用一个结构体，存储时间:年月日)设计程序按病患姓名实现病患的查找。如果找到该病患信息，就在屏幕上显示出该人的所有信息，如果没有找到，则显示“查无此人“

以下是一个基本的C++代码实现：

#include <iostream>
#include <string>
using namespace std;

struct Date {
    int year;
    int month;
    int day;
};

struct MedicalRecord {
    int id;
    string name;
    int age;
    string gender;
    string symptoms;
    string diagnosis;
    Date visitDate;
};

const int MAX_RECORDS = 100; // 最大病历数

int main() {
    MedicalRecord records[MAX_RECORDS]; // 定义病历数组
    int count = 0; // 记录当前的病历数

    // 示例数据，实际应用中可通过读写文件、数据库等方式获取
    records[count++] = { 1001, "张三", 30, "男", "头痛、发烧、咳嗽", "感冒", { 2021, 10, 1 } };
    records[count++] = { 1002, "李四", 45, "女", "腰痛", "腰椎间盘突出", { 2021, 9, 15 } };
    records[count++] = { 1003, "王五", 60, "男", "胸痛、气短", "冠心病", { 2021, 10, 5 } };

    string searchName;
    cout << "请输入要查找的病患姓名：";
    cin >> searchName;

    bool found = false; // 标记是否找到匹配的病患信息
    for (int i = 0; i < count; i++) {
        if (records[i].name == searchName) {
            found = true;
            // 显示病患信息
            cout << "病历号：" << records[i].id << endl;
            cout << "姓名：" << records[i].name << endl;
            cout << "年龄：" << records[i].age << endl;
            cout << "性别：" << records[i].gender << endl;
            cout << "症状：" << records[i].symptoms << endl;
            cout << "初诊情况：" << records[i].diagnosis << endl;
            cout << "就诊时间：" << records[i].visitDate.year << "年"
                 << records[i].visitDate.month << "月"
                 << records[i].visitDate.day << "日" << endl;
            break; // 找到一个匹配的病患信息即可退出循环
        }
    }

    if (!found) {
        cout << "查无此人" << endl;
    }

    return 0;
}

注：本代码仅作为示例，实际应用中需要针对具体需求进行修改和完善。