python遗传算法代码实现典型的物流配送问题
时间: 2023-08-07 22:36:39 浏览: 209
好的,下面是一个 Python 实现的遗传算法,用于解决典型的物流配送问题:
```python
import random
# 工地和料场的位置和需求量
locations = [{'name': 'A', 'x': 5, 'y': 1, 'demand': 5},
{'name': 'B', 'x': 2, 'y': 7, 'demand': 7},
{'name': 'C', 'x': 6, 'y': 6, 'demand': 8},
{'name': 'D', 'x': 1, 'y': 3, 'demand': 6},
{'name': 'E', 'x': 7, 'y': 2, 'demand': 3},
{'name': 'F', 'x': 2, 'y': 5, 'demand': 2}]
# 料场的位置和储量
depots = [{'name': 'A', 'x': 5, 'y': 1, 'supply': 20},
{'name': 'B', 'x': 2, 'y': 7, 'supply': 20}]
# 遗传算法参数
POP_SIZE = 100 # 种群大小
GENE_SIZE = len(locations) * len(depots) # 基因长度
CROSS_RATE = 0.8 # 交叉概率
MUTATION_RATE = 0.01 # 变异概率
N_GENERATIONS = 200 # 迭代次数
# 生成随机个体
def generate_individual():
individual = []
for i in range(GENE_SIZE):
# 随机生成每个基因的值,即从一个节点到另一个节点运输的吨数
individual.append(random.randint(0, 20))
return individual
# 计算个体的适应度
def calculate_fitness(individual):
# 将个体的基因编码转换成矩阵形式,方便计算
matrix = []
for i in range(len(depots)):
row = []
for j in range(len(locations)):
row.append(individual[i * len(locations) + j])
matrix.append(row)
# 计算每个工地的需求量和每个料场的供应量
demands = [loc['demand'] for loc in locations]
supplies = [depot['supply'] for depot in depots]
# 初始化每个节点的剩余需求量和供应量
remaining_demands = list(demands)
remaining_supplies = list(supplies)
# 计算每个节点之间的距离和运输量
total_distance = 0
for i in range(len(matrix)):
for j in range(len(matrix[i])):
distance = ((depots[i]['x'] - locations[j]['x']) ** 2 + (depots[i]['y'] - locations[j]['y']) ** 2) ** 0.5
total_distance += distance * matrix[i][j]
remaining_demands[j] -= matrix[i][j]
remaining_supplies[i] -= matrix[i][j]
# 计算剩余供应量和需求量的总和
total_remaining_demand = sum([max(0, d) for d in remaining_demands])
total_remaining_supply = sum([max(0, s) for s in remaining_supplies])
# 计算适应度,即总吨千米数
fitness = total_distance + total_remaining_demand + total_remaining_supply
return fitness
# 选择操作
def selection(population):
# 计算每个个体的适应度
fitnesses = [calculate_fitness(individual) for individual in population]
# 选择适应度最高的前一半个体
sorted_population = [x for _, x in sorted(zip(fitnesses, population))]
half = len(sorted_population) // 2
selected_population = sorted_population[:half]
return selected_population
# 交叉操作
def crossover(parent1, parent2):
# 随机选择一个交叉点
crossover_point = random.randint(0, GENE_SIZE - 1)
# 交叉操作
child1 = parent1[:crossover_point] + parent2[crossover_point:]
child2 = parent2[:crossover_point] + parent1[crossover_point:]
return child1, child2
# 变异操作
def mutation(individual):
# 随机选择一个基因进行变异
mutation_point = random.randint(0, GENE_SIZE - 1)
# 变异操作
individual[mutation_point] = random.randint(0, 20)
return individual
# 遗传算法主程序
def genetic_algorithm():
# 生成初始种群
population = [generate_individual() for _ in range(POP_SIZE)]
# 迭代 N_GENERATIONS 次
for generation in range(N_GENERATIONS):
print('Generation:', generation)
# 选择操作
selected_population = selection(population)
# 交叉操作
for i in range(0, len(selected_population), 2):
parent1 = selected_population[i]
parent2 = selected_population[i + 1]
if random.random() < CROSS_RATE:
child1, child2 = crossover(parent1, parent2)
selected_population[i] = child1
selected_population[i + 1] = child2
# 变异操作
for i in range(len(selected_population)):
if random.random() < MUTATION_RATE:
selected_population[i] = mutation(selected_population[i])
# 生成新种群
new_population = selected_population + [generate_individual() for _ in range(POP_SIZE - len(selected_population))]
# 更新种群
population = new_population
# 选择适应度最高的个体
fitnesses = [calculate_fitness(individual) for individual in population]
fittest_individual = population[fitnesses.index(min(fitnesses))]
return fittest_individual
# 测试
best_individual = genetic_algorithm()
print('Best individual:', best_individual)
```
在这个例子中,我们首先定义了工地和料场的位置、需求量、储量等参数。然后,我们定义了遗传算法的参数,如种群大小、基因长度等。接着,我们实现了生成随机个体、计算适应度、选择、交叉和变异等遗传算子,以及遗传算法的主程序。最后,我们通过调用主程序,得到最优解。
需要注意的是,由于 Python 的运行速度较慢,因此在处理大规模的问题时可能需要更长的运行时间。同时,由于遗传算法本身的随机性,可能会得到不同的结果。因此,在实际应用中,需要多次运行算法,取多次结果的平均值作为最终结果。
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