输入n,求1!+2!+3!+4!+…+n!循环的嵌套C++
时间: 2023-11-20 10:06:45 浏览: 27
以下是输入n,求1!+2!+3!+4!+…+n!循环的嵌套C++代码:
```c++
#include <iostream>
using namespace std;
int main() {
int n;
int sum = 0;
int team = 1;
cout << "请输入n的值:";
cin >> n;
if (n <= 0) {
cout << "n为正整数,请重新输入" << endl;
return 0;
}
for (int i = 1; i <= n; i++) {
team = 1;
for (int j = 1; j <= i; j++) {
team *= j;
}
sum += team;
}
cout << "该式的值为:" << sum << endl;
return 0;
}
```
相关问题
c++ 1!+3!+5!+7!+n!内循环嵌套设计 n<12
下面是一个使用循环嵌套计算1!+3!+5!+7!+n!的C++程序,其中n<12:
```
#include <iostream>
using namespace std;
int main() {
int n, sum = 0, f = 1;
cout << "请输入 n 的值:";
cin >> n;
for (int i = 1; i <= n; i += 2) {
f = 1;
for (int j = 1; j <= i; j++) {
f *= j;
}
sum += f;
}
cout << "1!+3!+5!+7!+...+" << n << "! = " << sum << endl;
return 0;
}
```
程序先通过 `cin` 获取用户输入的 `n` 值,然后使用两层循环计算阶乘并累加到 `sum` 变量中,最后输出结果。其中第一层循环控制奇数的范围,第二层循环计算阶乘。
求1!+2!+3!+4!+5!+…+n!的和 cpp
以下是两种C++求1!+2!+3!+4!+5!+…+n!的和的例子:
1.使用for循环计算阶乘和
```cpp
#include<iostream>
using namespace std;
int main()
{
int n;
unsigned long long m = 1;
unsigned long long z = 0;
cout << "请输入n的值:";
cin >> n;
for (int i = 1; i <= n; i++)
{
m *= i;
z += m;
}
cout << "1!+2!+3!+...+" << n << "!的和为:" << z << endl; return 0;
}
```
2.使用嵌套for循环计算阶乘和
```cpp
#include<stdio.h>
int main()
{
int i, j, n;
int sum = 0;
int team = 1;
printf("请输入n的值:");
scanf("%d", &n);
if (n <= 0)
{
printf("n为正整数,请重新输入\n");
}
for (i = 1; i <= n; i++)
{
for (j = 1; j <= i; j++)
{
team = team * j;
}
sum = team + sum;
team = 1;
}
printf("1!+2!+3!+...+%d!的和为:%d", n, sum);
return 0;
}
```