用c++代码写一个扫雷小游戏

以下是用C++代码实现扫雷小游戏的基本步骤：

//定义常量
const int N = 105;
const int M = 105;
const int dx[8] = {0, 0, 1, -1, 1, 1, -1, -1};
const int dy[8] = {1, -1, 0, 0, 1, -1, 1, -1};

//定义变量
int n, m, k, cnt;
char a[N][M], b[N][M];
bool vis[N][M];

//初始化
void init() {
    memset(a, '.', sizeof(a));
    memset(b, '0', sizeof(b));
    memset(vis, false, sizeof(vis));
    cnt = 0;
}

//生成雷区
void build() {
    while (cnt < k) {
        int x = rand() % n + 1;
        int y = rand() % m + 1;
        if (a[x][y] == '*') continue;
        a[x][y] = '*';
        cnt++;
    }
}

//计算周围雷数
void calc() {
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            if (a[i][j] == '*') continue;
            for (int k = 0; k < 8; k++) {
                int x = i + dx[k];
                int y = j + dy[k];
                if (x < 1 || x > n || y < 1 || y > m) continue;
                if (a[x][y] == '*') b[i][j]++;
            }
        }
    }
}

//递归展开
void dfs(int x, int y) {
    vis[x][y] = true;
    if (b[x][y] != '0') return;
    for (int i = 0; i < 8; i++) {
        int nx = x + dx[i];
        int ny = y + dy[i];
        if (nx < 1 || nx > n || ny < 1 || ny > m) continue;
        if (vis[nx][ny]) continue;
        dfs(nx, ny);
    }
}

//主函数
int main() {
    srand(time(NULL));
    cin >> n >> m >> k;
    init();
    build();
    calc();
    dfs(1, 1);
    for (int i = 1; i <= n; i++) {
        for (int j = 1; j <= m; j++) {
            if (vis[i][j]) cout << b[i][j];
            else cout << ".";
        }
        cout << endl;
    }
    return 0;
}