（2）用do-while语句计算1+1/2+1/3+……+1/n.

#include <stdio.h>

int main() {
    int n = 1;
    float sum = 0;
    do {
        sum += 1.0 / n;
        n++;
    } while (n <= 10);
    printf("1+1/2+1/3+...+1/n=%f", sum);
    return 0;
}