Write a Python function to check whether a string is pangram or not. (Assume the string passed in does not have any punctuation)

当然可以，首先你需要了解什么是帕格拉姆（Pangram），它是指包含英语字母表所有26个字母的句子或短语。下面是一个简单的Python函数，用于检查给定字符串是否为帕格拉姆：

def is_pangram(s):
    alphabet = "abcdefghijklmnopqrstuvwxyz"
    for char in alphabet:
        if char not in s.lower():
            return False
    return True

# 测试示例
s = "The quick brown fox jumps over the lazy dog"
if is_pangram(s):
    print(f"{s} is a pangram.")
else:
    print(f"{s} is not a pangram.")

# 使用这个函数检查输入的字符串是否为帕格拉姆
input_string = input("Enter a string without punctuation: ")
if is_pangram(input_string):
    print("The string is a pangram.")
else:
    print("The string is not a pangram.")

相关问题

Implement about, which takes a list of topic words. It returns a function that can be passed to choose as the select argument. The returned function takes a paragraph and returns a boolean indicating whether that paragraph contains any of the words in topic. To make this comparison accurately, you will need to ignore case (that is, assume that uppercase and lowercase letters don't change what word it is) and punctuation. Assume that all words in the topic list are already lowercased and do not contain punctuation.

Sure, I can help you with that.

Here's an implementation of the `about` function you described:

import string

def about(topic):
    def contains_topic_word(paragraph):
        # Remove punctuation from paragraph
        paragraph = paragraph.translate(str.maketrans('', '', string.punctuation))
        
        # Convert paragraph to lowercase
        paragraph = paragraph.lower()
        
        # Check if any word in the paragraph is in the topic list
        for word in paragraph.split():
            if word in topic:
                return True
        
        return False
    
    return contains_topic_word

This function takes a list of topic words and returns a function that can be passed to the `choose` function's `select` argument. The returned function takes a paragraph and returns a boolean indicating whether that paragraph contains any of the words in the topic list. It removes punctuation from the paragraph, converts it to lowercase, and checks if any word in the paragraph is in the topic list.

Here's an example usage of this function:

topic = ['python', 'programming', 'language']
contains_topic_word = about(topic)

paragraph = "Python is a high-level programming language. It is widely used for web development, scientific computing, data analysis, artificial intelligence, and more."

if contains_topic_word(paragraph):
    print("This paragraph is about Python programming language.")
else:
    print("This paragraph is not about Python programming language.")

Output:

This paragraph is about Python programming language.

I hope this helps! Let me know if you have any questions.

Please write a code to check whether a user' inputted password is correct or not. If the password is correct, then print out “correct” and stop the program, otherwise print “false, try again”. Let user try another time without chance limitation. (assume that password equals to '12345').

以下是使用Python编写的代码，用于检查用户输入的密码是否正确：

password = '12345'
while True:
    user_input = input('请输入密码：')
    if user_input == password:
        print('密码正确')
        break
    else:
        print('密码错误，请重试')

代码首先定义了正确的密码为`12345`，然后进入一个无限循环，允许用户不限次数地输入密码。

在每次循环中，代码提示用户输入密码，并将其存储在`user_input`变量中。

然后，代码检查`user_input`是否等于正确的密码。如果是，则打印“密码正确”，并使用`break`语句停止循环。否则，代码打印“密码错误，请重试”，并重新开始下一轮循环，让用户重新尝试输入密码。

这个循环会一直运行，直到用户输入了正确的密码才会停止。