CREATE OR REPLACE FUNCTION check_continuous_days(input_dates IN VARCHAR2) RETURN NUMBER IS date_array DBMS_UTILITY.uncl_array; day_diff NUMBER; continuous_day NUMBER := 1; BEGIN -- 将输入的日期字符串解析为日期数组 date_array := DBMS_UTILITY.comma_to_table(input_dates); -- 按照日期顺序比较相邻两个日期之间的天数差 FOR i IN 2..date_array.count LOOP day_diff := date_array(i) - date_array(i-1); IF day_diff = 1 THEN continuous_day := continuous_day + 1; ELSE continuous_day := 1; END IF; END LOOP; -- 返回连续的天数 RETURN continuous_day; END;

时间: 2024-04-05 21:34:17 浏览: 117
这是一个Oracle函数,用于检查输入的日期字符串中连续的天数。具体而言,该函数的输入参数为一个包含多个日期的字符串,每个日期之间用逗号分隔,例如'2022-01-01,2022-01-02,2022-01-03'。函数的返回值为连续的天数,即输入日期字符串中连续的日期的个数。 函数的实现思路如下: 1. 将输入的日期字符串解析为日期数组; 2. 比较相邻两个日期之间的天数差,若为1则表示两个日期是连续的,否则表示两个日期不连续,重新开始计算连续的天数; 3. 返回连续的天数。 例如,如果输入的日期字符串为'2022-01-01,2022-01-02,2022-01-03,2022-01-05,2022-01-06',则函数的返回值为3,表示在输入的日期字符串中有3个连续的日期。
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WITH RECURSIVE dates AS ( SELECT "2021-12-01" AS date UNION ALL SELECT date + INTERVAL 1 DAY FROM dates WHERE date < "2023-03-27" ) SELECT DATE_FORMAT(dates.date, '%Y-%m-%d') AS date, IFNULL(COUNT(skins_logs.created_at), 0) AS count FROM dates LEFT JOIN skins_logs ON DATE(skins_logs.created_at) = dates.date AND skins_logs.skins_id = 481 WHERE dates.date BETWEEN "2021-12-01" AND "2023-03-27" GROUP BY dates.date;

如果您使用Flask和SQLAlchemy,可以使用以下代码将该查询转换为SQLAlchemy的查询: ```python from datetime import datetime, timedelta from sqlalchemy import func from yourapp import db class SkinLog(db.Model): __tablename__ = 'skins_logs' id = db.Column(db.Integer, primary_key=True) skins_id = db.Column(db.Integer, nullable=False) created_at = db.Column(db.DateTime, default=datetime.utcnow, nullable=False) start_date = datetime(2021, 12, 1).date() end_date = datetime(2023, 3, 27).date() dates = db.session.query( func.date_union(start_date, end_date, interval=1), func.date_format(func.date_union(start_date, end_date, interval=1), '%Y-%m-%d') ).subquery() counts = db.session.query( dates.c.date.label('date'), func.ifnull(func.count(SkinLog.created_at), 0).label('count') ).outerjoin( SkinLog, func.date(SkinLog.created_at) == dates.c.date, ).filter( SkinLog.skins_id == 481, dates.c.date.between(start_date, end_date), ).group_by( dates.c.date ).all() ``` 这里首先定义了SkinLog模型类来映射skins_logs表。然后根据查询语句中的日期序列生成方式,使用SQLAlchemy的date_union函数生成日期序列。然后将日期序列与SkinLog表进行左连接,并按日期分组计算每个日期在SkinLog表中的记录数。最后使用filter来过滤出与skins_id为481相关的记录,并在查询结果中使用ifnull函数将没有记录的日期的记录数设置为0。最后使用all方法执行查询并返回结果。

UnicodeDecodeError Traceback (most recent call last) <ipython-input-13-d8bda818b845> in <module> 1 import pandas as pd 2 from IPython.display import display ----> 3 data = pd.read_csv('goods.csv', encoding='utf-8') 4 data.insert(2, 'goods', '') 5 def get_goods(title): C:\u01\anaconda3\lib\site-packages\pandas\io\parsers.py in read_csv(filepath_or_buffer, sep, delimiter, header, names, index_col, usecols, squeeze, prefix, mangle_dupe_cols, dtype, engine, converters, true_values, false_values, skipinitialspace, skiprows, skipfooter, nrows, na_values, keep_default_na, na_filter, verbose, skip_blank_lines, parse_dates, infer_datetime_format, keep_date_col, date_parser, dayfirst, cache_dates, iterator, chunksize, compression, thousands, decimal, lineterminator, quotechar, quoting, doublequote, escapechar, comment, encoding, dialect, error_bad_lines, warn_bad_lines, delim_whitespace, low_memory, memory_map, float_precision, storage_options) 608 kwds.update(kwds_defaults) 609 --> 610 return _read(filepath_or_buffer, kwds) 611 612 C:\u01\anaconda3\lib\site-packages\pandas\io\parsers.py in _read(filepath_or_buffer, kwds) 460 461 # Create the parser. --> 462 parser = TextFileReader(filepath_or_buffer, **kwds) 463 464 if chunksize or iterator: C:\u01\anaconda3\lib\site-packages\pandas\io\parsers.py in __init__(self, f, engine, **kwds) 817 self.options["has_index_names"] = kwds["has_index_names"] 818 --> 819 self._engine = self._make_engine(self.engine) 820 821 def close(self): C:\u01\anaconda3\lib\site-packages\pandas\io\parsers.py in _make_engine(self, engine) 1048 ) 1049 # error: Too many arguments for "ParserBase" -> 1050 return mapping[engine](self.f, **self.options) # type: ignore[call-arg] 1051 1052 def _failover_to_python(self): C:\u01\anaconda3\lib\site-packages\pandas\io\parsers.py in __init__(self, src, **kwds) 1896 1897 try: -> 1898 self._reader = parsers.TextReader(self.handles.handle, **kwds) 1899 except Exception: 1900 self.handles.close() pandas\_libs\parsers.pyx in pandas._libs.parsers.TextReader.__cinit__() pandas\_libs\parsers.pyx in pandas._libs.parsers.TextReader._get_header() pandas\_libs\parsers.pyx in pandas._libs.parsers.TextReader._tokenize_rows() pandas\_libs\parsers.pyx in pandas._libs.parsers.raise_parser_error() UnicodeDecodeError: 'utf-8' codec can't decode byte 0xca in position 83: invalid continuation byte

这个错误通常是由于在读取文件时指定的编码与实际编码不匹配导致的。在这种情况下,建议尝试使用其他编码格式重新读取文件。你可以尝试使用 "GBK" 或 "GB2312" 等中文编码格式。例如,你可以这样修改代码: ```python data = pd.read_csv('goods.csv', encoding='GBK') ``` 如果还是无法解决问题,建议检查文件本身是否存在编码问题,可能需要在其他编辑器中重新保存文件并指定正确的编码格式。
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# 连接到MySQL 数据库 conn = mysql.connector.connect( host='120.78.240.31', user='game', password='LmmaFmxZ7M7r7LAh', database='game', charset='utf8' ) cursor = conn.cursor() # 查询示例数据 cursor.execute('SELECT zs_library.id,zs_library.number, zs_library.zs_name,game.game_name,zs_library.txt_url,' 'zs_library.tupian_url1,zs_library.tupian_url2,zs_library.tupian_url3,zs_library.tupian_url4,' 'zs_library.tupian_url5,zs_library.tupian_url6,zs_library.tupian_url7,zs_library.tupian_url8,' 'zs_library.tupian_url9,zs_library.tupian_url10,zs_library.tupian_url11,zs_library.tupian_url12,' 'zs_library.tupian_url13,zs_library.tupian_url14,zs_library.tupian_url15,zs_library.tupian_url16,' 'zs_library.tupian_url17,zs_library.tupian_url18,zs_library.tupian_url19,zs_library.tupian_url20,' 'zs_library.dates FROM zs_library JOIN game ON ' 'zs_library.game_id = game.id WHERE zs_library.id=%s',(int(zs_library_id),)) items = cursor.fetchall() arr = [] arrsd = [] for k in range(0, len(items[0])): if k == 1 or k == 2 or k == 3 or k == 4: arr.append(items[0][k].decode("utf-8")) elif k == 5 or k == 6 or k == 7 or k == 8 or k == 9 or k == 10 or k == 11 or k == 12 or k == 13 or k == 14 or k == 15 or k == 16 or k == 17\ or k == 18 or k == 19 or k == 20 or k == 21 or k == 22 or k == 23 or k == 24: if items[0][k]: arrsd.append(items[0][k]) else: arrsd.append('') else: arr.append(items[0][k]) # 获取对应数据库的内容 with open(arr[4], "r", encoding="utf-8") as file: content = file.read() new_content = content.replace("\n\n", "

") return template("gameedit.html", number=number, items=arr,arrsd='_*'.join(arrsd), id=id,content=new_content)

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Write a C++ program that defines a class DateV2 that (1) Contains all the members in the class DateV1; Programming for Engineers C++ (2) Has two constructors as follows: One takes three parameters, int y, int m, int n; The other is the default constructor that takes no parameter (3) Has additional public member functions as follows: string getWeekDay(); // return the week day, for example, Sunday if day is 0, etc bool Leap(); // return if the year is leap int differFrom(DateV2& oneDate); // return the difference in days between the calling object // and the oneDate object void printDate(); // print the year, the month in English, the day, and the week day Test class DateV2 in the main function as follows: (1) Declare and set the objects today and tomorrow as in Problem 2. (2) Declare and initialize (by a constructor) an object to represent your OWN birthday. (3) Use the member function printDate to print today, tomorrow, and your birthday. (4) Output the weekday of today, tomorrow, and your own birthday. (5) Output how many days has passed since your birth (the difference between your birthday and today). Hint: i) We can use another string array to store the English name for week days (Sunday, Monday, through Saturday) ii) We know that it is Monday on Year 1, Month 1, and Day 1 iii) A good idea is to first design a function to compute the number of days that has passed since Year 1, Month 1, and Day 1, and then to use this function to compute the week day for a give date and to compute the difference between two dates. You can store the number of days for each of the 12 months in an integer array, which helps in counting the days.

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Write a C++ program that defines a class DateV3 with the following: (1) private member variables: int year, month, day; (2) Has three constructors and one destructor as follows: The first constructor takes three parameters, int y, int m, int n; The second is the copy constructor that takes a DateV3 object as the parameter; The third is the default constructor that takes no parameter; The destructor takes no parameter. (3) Has overloaded operators: int operator-(DateV3 & oneDate); // return difference in days between the calling object and oneDate DateV3 operator+(int inc); // return a Date object that is inc days later than the calling object DateV3 operator-(int dec); // return a Date object that is dec days earlier than the calling object DateV3 operator++(); // overload the prefix ++ operator DateV3 operator++(int); // overload the postfix ++ operator friend ostream& operator<< (ostream& outputStream, DateV3& theDate); // overload the << operator Test class DateV3 in the main function as follows: (1) Declare and initialize an object to represent today, which should be the date that you work on this assignment. (2) Declare and initialize an object to represent your OWN birthday. (3) Express John’s birthday given John is 5 days older than yours. (4) Create Tom’s birthday by using the copy constructor, assuming Tom has the same birthday as you. (5) Display how many days have passed since your birth, John’s birth, and Tom’s birth, respectively. (6) Create an DateV3 object, someday, by cloning Tom’s birthday. Increment someday by the prefix operator ++ once, and by postfix operator ++ once. (7) Display someday, today, your birthday, John’s birthday, and Tom’s birthday. (8) Declare a DateV3 object to represent 28 February 2024, display it, apply the prefix ++ operator on it, display it again, and apply the postfix ++ operator on it and display it again. Hint: i) A good idea is to first design a function to compute the number of days that has passed since Year 1, Month 1, and Day 1, and then to use this function to compute the difference between two dates. ii) You can store the number of days for each of the 12 months in an integer array, which helps in counting the days and implementing the overloaded operators.

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