用verilog写一个4x4矩阵键盘的代码
时间: 2023-08-13 18:03:46 浏览: 169
verilog 4×4矩阵键盘
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下面是一个简单的4x4矩阵键盘的Verilog代码:
```
module matrix_keypad(input wire [3:0] row, input wire [3:0] col, output reg [15:0] key);
reg [3:0] row_sel;
reg [3:0] col_sel;
wire [3:0] row_scan;
wire [3:0] col_scan;
// 行扫描器,将行选择信号轮流设为高电平
always @ (posedge clk) begin
row_sel <= row_sel + 1;
if (row_sel == 4) row_sel <= 0;
end
// 列扫描器,检测列扫描信号是否为高电平
always @ (posedge clk) begin
col_sel <= col_sel + 1;
if (col_sel == 4) col_sel <= 0;
end
// 矩阵键盘行扫描
assign row_scan = {~row[0], ~row[1], ~row[2], ~row[3]};
// 矩阵键盘列扫描
assign col_scan = {col[0], col[1], col[2], col[3]};
// 检测按键是否按下
always @ (posedge clk) begin
if ((row_scan & (1 << row_sel)) && (col_scan & (1 << col_sel))) begin
key <= (row_sel << 2) | col_sel; // 将按下的按键编码输出
end
end
endmodule
```
该代码使用一个row信号和一个col信号来读取4x4矩阵键盘的输入。它将键码编码为16位输出信号,并在检测到按键按下时输出该信号。该代码还包括行扫描器和列扫描器,它们轮流选择行和列进行扫描。
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