Find the smallest integer in the array 使用python语法
时间: 2023-12-03 22:42:43 浏览: 45
可以使用Python中的min函数来找到数组中的最小值,示例如下:
```python
arr = [3, 5, 2, 8, 1]
smallest = min(arr)
print(smallest) # 输出1
```
其中,arr是一个包含整数的数组,min函数返回数组中的最小值,将其赋值给变量smallest,并打印输出。
相关问题
(Algebra: perfect square) Write a program that prompts the user to enter an integer m and find the smallest integer n such that m * n is a perfect square. (Hint: Store all smallest factors of m into an array list. n is the product of the factors that appear an odd number of times in the array list. For example, consider m = 90, store the factors 2, 3, 3, and 5 in an array list. 2 and 5 appear an odd number of times in the array list. Thus, n is 10.)
Here's a Python program that implements the algorithm described in the problem statement:
```
import math
def smallest_perfect_square_factor(m):
factors = []
# Find all smallest factors of m
while m % 2 == 0:
factors.append(2)
m = m // 2
for i in range(3, int(math.sqrt(m))+1, 2):
while m % i == 0:
factors.append(i)
m = m // i
if m > 2:
factors.append(m)
# Compute n as the product of factors that appear an odd number of times
odd_factors = [x for x in factors if factors.count(x) % 2 == 1]
n = 1
for f in odd_factors:
n *= f
return n
m = int(input("Enter an integer m: "))
n = smallest_perfect_square_factor(m)
print(f"The smallest integer n such that m * n is a perfect square is {n}.")
```
The program first computes all the smallest factors of `m` and stores them in an array list called `factors`. Then, it identifies the factors that appear an odd number of times in the list, and multiplies them together to obtain `n`. Finally, the program prints out the value of `n`.
given an array length 1 or more of ints, return the difference between the largest and the smallest values in the arrey
Sure, I can help you with that! Here's a Python function that takes an array of integers and returns the difference between the largest and smallest values:
```python
def array_diff(nums):
return max(nums) - min(nums)
```
You can call this function with an array of integers like this:
```python
nums = [4, 8, 1, 9, 3]
diff = array_diff(nums)
print(diff) # Output: 8
```
This will output the difference between the largest and smallest values in the `nums` array, which is 8 in this case. Let me know if you have any other questions!
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