given an array length 1 or more of ints, return the difference between the largest and the smallest values in the arrey
时间: 2024-02-24 21:54:12 浏览: 29
Sure, I can help you with that! Here's a Python function that takes an array of integers and returns the difference between the largest and smallest values:
```python
def array_diff(nums):
return max(nums) - min(nums)
```
You can call this function with an array of integers like this:
```python
nums = [4, 8, 1, 9, 3]
diff = array_diff(nums)
print(diff) # Output: 8
```
This will output the difference between the largest and smallest values in the `nums` array, which is 8 in this case. Let me know if you have any other questions!
相关问题
Write a program to determine and display the smallest and largest valuescontained in 99-elcment floating-point array w.
Sure, here's a program in C to determine and display the smallest and largest values contained in a 99-element floating-point array `w`:
```c
#include <stdio.h>
int main() {
float w[99]; // declare the array
float smallest, largest; // variables to store the smallest and largest values
// code to fill the array with values goes here
// initialize smallest and largest to the first element of the array
smallest = w[0];
largest = w[0];
// loop through the array and update smallest and largest as necessary
for (int i = 1; i < 99; i++) {
if (w[i] < smallest) {
smallest = w[i];
}
if (w[i] > largest) {
largest = w[i];
}
}
// display the smallest and largest values
printf("Smallest value: %f\n", smallest);
printf("Largest value: %f\n", largest);
return 0;
}
```
Note that you'll need to add code to fill the array `w` with values before the loop that determines the smallest and largest values.
Write a C++ program to determine and display the smallest and largest valuescontained in 99-elcment floating-point array w.
Sure, here's a program in C++ to determine and display the smallest and largest values contained in a 99-element floating-point array `w`:
```cpp
#include <iostream>
#include <limits> // needed for numeric_limits
int main() {
float w[99]; // declare the array
float smallest, largest; // variables to store the smallest and largest values
// code to fill the array with values goes here
// initialize smallest and largest to the first element of the array
smallest = w[0];
largest = w[0];
// loop through the array and update smallest and largest as necessary
for (int i = 1; i < 99; i++) {
if (w[i] < smallest) {
smallest = w[i];
}
if (w[i] > largest) {
largest = w[i];
}
}
// display the smallest and largest values
std::cout << "Smallest value: " << smallest << std::endl;
std::cout << "Largest value: " << largest << std::endl;
return 0;
}
```
Note that you'll need to add code to fill the array `w` with values before the loop that determines the smallest and largest values. Also, in C++ we can use `numeric_limits` from the `<limits>` header to initialize `smallest` and `largest` to the maximum and minimum possible values for a float, respectively, like this:
```cpp
float smallest = std::numeric_limits<float>::max();
float largest = std::numeric_limits<float>::min();
```
This way, we don't need to assume that the first element of the array is the smallest or largest.