def fun(n): sum = 0 for i in range(2, n+1, 2): sum += i return sumresult = fun(100)print("1~100中偶数之和为:", result)
时间: 2023-12-10 16:04:31 浏览: 55
抱歉,上面的代码排版有误,已经无法执行。以下是正确的代码:
```python
def fun(n):
sum = 0
for i in range(2, n+1, 2):
sum += i
return sum
result = fun(100)
print("1~100中偶数之和为:", result)
```
输出结果为:
```
1~100中偶数之和为: 2550
```
请注意,该函数只计算1~n中的偶数之和,因此在调用fun(n)时,需要将n的值设置为100。
相关问题
import math def fun(n): sum = 1 for i in range(2, int(math.sqrt(n))+1): if n % i == 0: sum += i if i != n // i: sum += n // i if sum == n and n != 1: return 1 else: return0 n = int(input("请输入一个整数:")) if fun(n): print(n, "是完数") else: print(n, "不是完数")注释
下面是对程序的详细注释:
```python
import math # 导入 math 模块
def fun(n): # 定义函数 fun,用于判断一个整数是否为完数
sum = 1 # 初始化因子之和为 1
for i in range(2, int(math.sqrt(n))+1): # 循环遍历 2 到 sqrt(n) 之间的整数
if n % i == 0: # 若 i 是 n 的因子
sum += i # 将 i 加入到因子之和中
if i != n // i: # 若 i 不是 n 的平方根
sum += n // i # 将 n/i 加入到因子之和中
if sum == n and n != 1: # 若因子之和等于 n 且 n 不等于 1
return 1 # 返回 1,表示 n 是完数
else:
return 0 # 返回 0,表示 n 不是完数
n = int(input("请输入一个整数:")) # 输入一个整数 n
if fun(n): # 若 fun(n) 返回值为 1
print(n, "是完数") # 输出 n 是完数
else:
print(n, "不是完数") # 输出 n 不是完数
```
def fun3(X): O=0 for i in range(len(X)): O=O+np.square(np.sum(X[0:i+1])) return O
As an AI language model, I can infer that the given code is a Python function named "fun3" that takes a single argument X as input. The function initializes a variable "O" to zero and then iterates over the elements of the input X using a for loop. In each iteration, it calculates the square of the sum of the elements from the beginning of the input up to the current index (excluding the element at the current index) using the numpy library's "np.square" and "np.sum" functions. Finally, the function returns the value of "O", which would be the sum of the squares of the partial sums of the input X.
However, the code has some syntax errors, specifically in the line "O=O np.square(np.sum(X[0:i 1]))", where there should be an operator between "O" and "np.square". It is also unclear what the purpose of the function is or how it would be used in practice.