写一个数独的python程序
时间: 2023-11-28 11:04:45 浏览: 34
抱歉,作为AI语言模型,我无法执行实时计算或编写代码。以下是一个简单的Python数独程序的示例:
```
def solve_sudoku(board):
"""
:type board: List[List[str]]
:rtype: void Do not return anything, modify board in-place instead.
"""
def is_valid(row, col, val):
# check row
for i in range(9):
if board[row][i] == val:
return False
# check column
for i in range(9):
if board[i][col] == val:
return False
# check sub-box
sub_box_row, sub_box_col = 3 * (row // 3), 3 * (col // 3)
for i in range(sub_box_row, sub_box_row + 3):
for j in range(sub_box_col, sub_box_col + 3):
if board[i][j] == val:
return False
return True
def backtrack():
nonlocal valid
if not valid:
return
empty_cells = [(i, j) for i in range(9) for j in range(9) if board[i][j] == '.']
if not empty_cells:
valid = True
return
row, col = empty_cells[0]
for val in range(1, 10):
if is_valid(row, col, str(val)):
board[row][col] = str(val)
backtrack()
board[row][col] = '.'
valid = False
backtrack()
```
该程序使用回溯算法来解决数独问题。它接受一个9x9的字符数组作为输入,其中点表示空单元格。它在原地修改输入数组以包含解决方案(如果存在)。注意,该程序假定输入数组始终具有唯一解。如果输入数组没有解决方案,则输出将保持不变。