sum=0 for i in range(2,10,2): sum+=i print(sum)
时间: 2023-12-15 11:06:07 浏览: 89
This code will print out the value of sum after each iteration of the loop.
The loop starts at 2 and goes up to (but not including) 10, incrementing by 2 each time.
During each iteration, the value of i is assigned to sum. So on the first iteration, sum will be 2. On the second iteration, sum will be 4, and so on until the last iteration where sum will be 8.
Therefore, the output of this code will be:
2
4
6
8
相关问题
sum = 0 for i in range(1, 11): sum += i print(sum)
This code will output the value of the variable "sum" after each iteration of the for loop.
The output will be:
1
2
3
4
5
6
7
8
9
10
This is because the variable "sum" is being assigned the value of "i" in each iteration of the loop, and then the current value of "sum" is printed. Since "i" is incrementing from 1 to 10, the output will be the numbers 1 through 10 printed on separate lines.
Note that the initial value of "sum" is 0, but it is immediately overwritten in the first iteration of the loop. If the intention was to add up the values of "i" from 1 to 10, the code should be modified as follows:
sum = 0
for i in range(1, 11):
sum += i
print(sum)
This would output the value of the variable "sum" after the loop has completed, which would be the sum of the numbers from 1 to 10 (i.e. 55).
sum=0 for i in range(1,11): sum += i print( sum)
您的代码中,变量sum是初始值为0的累加器,但是在每次循环中,您将i直接赋值给了sum,而没有将i加入到sum中。因此,每次循环结束后,sum的值都将等于i的值。建议您将代码修改为以下形式:
sum = 0
for i in range(1, 11):
sum += i
print(sum)
这样,每次循环中都将i加入到sum中,循环结束后,sum的值就是1到10的和,即55。