a[1 : n.+ 1] = list(map(int, input().split()))
时间: 2024-05-18 19:14:36 浏览: 11
这段代码的作用是将输入的一行空格分隔的整数存储到列表a中的第1个到第n+1个元素中。其中n是一个整数,可以在代码中另外定义或者通过用户输入获得。具体来说,这段代码会先调用input()函数获取一行输入,然后调用split()函数将输入按空格切分成多个字符串,接着调用map()函数将每个字符串转换成整数,最后用列表切片的方式将转换后的整数存储到a中的指定位置。
相关问题
约瑟夫环改错class Node: def __init__(self,data): self.data=data self.next=Noneclass linklist: def __init__(self): self.head=None self.data=None def isEmpty(self): if self.head: return False else: return True def length(self): if self.isEmpty(): return 0 else: t = self.head n = 1 while t.next: if t.next == self.head: break t = t.next n = n + 1 return n def addhead(self,data): node = Node(data) if self.isEmpty(): self.head = node self.tail = self.head else: node.next = self.head self.head = node self.tail.next = self.head def addtail(self,data): node=Node(data) if self.isEmpty(): self.addhead(data) else: t=self.head n=1 l=self.length() while n<l: n=n+1 t=t.next t.next=node node.next=self.head self.tail=node def delete(self,index): if self.isEmpty(): print("The linked list is empty") else: t = self.head l = self.length() if index == 0: self.head = t.next self.tail.next = self.head elif index == l - 1: n = 1 while n < l - 1: t = t.next n = n + 1 t.next = self.head self.tail = t elif index > l - 1: print("Out of range") elif index < 0: print("Wrong operation") else: n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next.next t.next = a def insert(self,data,index): l = self.length() if index == 0 or self.isEmpty(): self.addhead(data) elif index >= l: self.addtail(data) else: node = Node(data) t = self.head n = 1 while n < index - 1: t = t.next n = n + 1 a = t.next t.next = node node.next = a def search(self,a): t=self.head for i in range(a): t=t.next return t.data def form(self,datalist): self.addhead(datalist[0]) for i in range(1,len(datalist)): self.addtail(datalist[i]) t = self.head while t.next != self.head: t = t.nextn,p=map(int,input().split(' '))data=[]p=p-1for i in range(1,n+1): data.append(i)print(data)datalist=[]for i in range(len(data)): datalist.append(int(data[i]))link=linklist()link.form(datalist)a=pb=[]while link.length()>0: b.append(link.search(a)) link.delete(a) a=a+p while a>=link.length(): a=a-link.length()print(b)
改错如下:
```python
class Node:
def __init__(self, data):
self.data = data
self.next = None
class LinkList:
def __init__(self):
self.head = None
self.tail = None
def isEmpty(self):
if self.head:
return False
else:
return True
def length(self):
if self.isEmpty():
return 0
else:
t = self.head
n = 1
while t.next:
if t.next == self.head:
break
t = t.next
n += 1
return n
def addhead(self, data):
node = Node(data)
if self.isEmpty():
self.head = node
self.tail = self.head
else:
node.next = self.head
self.head = node
self.tail.next = self.head
def addtail(self, data):
node = Node(data)
if self.isEmpty():
self.addhead(data)
else:
t = self.head
n = 1
l = self.length()
while n < l:
n += 1
t = t.next
t.next = node
node.next = self.head
self.tail = node
def delete(self, index):
if self.isEmpty():
print("The linked list is empty")
else:
t = self.head
l = self.length()
if index == 0:
self.head = t.next
self.tail.next = self.head
elif index == l - 1:
n = 1
while n < l - 1:
t = t.next
n += 1
t.next = self.head
self.tail = t
elif index > l - 1:
print("Out of range")
elif index < 0:
print("Wrong operation")
else:
n = 1
while n < index:
t = t.next
n += 1
a = t.next.next
t.next = a
def insert(self, data, index):
l = self.length()
if index == 0 or self.isEmpty():
self.addhead(data)
elif index >= l:
self.addtail(data)
else:
node = Node(data)
t = self.head
n = 1
while n < index:
t = t.next
n += 1
a = t.next
t.next = node
node.next = a
def search(self, a):
t = self.head
for i in range(a):
t = t.next
return t.data
def form(self, datalist):
self.addhead(datalist[0])
for i in range(1, len(datalist)):
self.addtail(datalist[i])
t = self.head
while t.next != self.head:
t = t.next
n, p = map(int, input().split(' '))
data = [i for i in range(1, n+1)]
print(data)
datalist = []
for i in range(len(data)):
datalist.append(data[i])
link = LinkList()
link.form(datalist)
a = p-1
b = []
while link.length() > 0:
b.append(link.search(a))
link.delete(a)
a += p-1
while a >= link.length():
a -= link.length()
print(b)
```
M,N=map(int,input().split()) list=[] for i in range(1,M+1): list.append(i) l=j=0 while list!=[]: for c in list: l+=1 j+=1 if l%N==0 and j==1: list=list[1::] print(c,end=" ") if l%N==0 and j!=len(list): list=list[0:j]+list[j+1::] print(c,end=" ") if l%N==0 and j==len(list): list=list[0:j] print(c,end=" ") j=0
这段代码是一个约瑟夫环问题的解法。输入M和N,表示M个人围成一个圆圈,从编号为1的人开始报数,报数为N的人出圈,然后从出圈的下一个人开始重新报数,直到剩下最后一个人为止。下面是代码的解释:
1. M, N=map(int,input().split()) # 输入M和N,分别表示人数和报数的值
2. list=[] # 创建一个空列表
3. for i in range(1,M+1): # 循环M次,将1~M的数字添加到列表中
4. list.append(i)
5. l=j=0 # 初始化l和j变量为0
6. while list!=[]: # 当列表不为空时循环
7. for c in list: # 循环遍历列表中的元素
8. l+=1 # 每循环一次,l加1
9. j+=1 # 每循环一次,j加1
10. if l%N==0 and j==1: # 如果报数为N并且是第一个人,直接删除该元素,并输出
11. list=list[1::] # 删除列表中的第一个元素
12. print(c,end=" ")
13. if l%N==0 and j!=len(list): # 如果报数为N并且不是最后一个人,删除该元素,并输出
14. list=list[0:j]+list[j+1::] # 删除列表中的第j个元素
15. print(c,end=" ")
16. if l%N==0 and j==len(list): # 如果报数为N并且是最后一个人,删除该元素,并输出
17. list=list[0:j] # 删除列表中的最后一个元素
18. print(c,end=" ")
19. j=0 # 将j变量重置为0,重新开始循环
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