运用Python3解决【】内的填空：n = int(input()) dic = {} for i in range(n): ls= input().split() score = 【_________________________】 if len(ls)==2: score *= 1.2 for 【_________________________】: dic[num] = score lt = [【_________________________】] lt.sort() for k, v in lt: print(k, v) [题目描述] Python课程设计的作业分小组完成，规定小组成员1-3人。为体现公平，凡是单人组队的，评分可以乘1.2系数。例如 :A和B同学组队，作品评分8分，则A和B同学各得8分;若C同学单独组，作品评分8分，则C同学得8*1.2=9.6分。现有多份作业数据(包括组员和评分)，请统计出每位同学的得分，并按学号升序输出。 [输入描述]第一行是一个整数n，接下去有n行，每行对应一份作业数据，先是组员的学号，未尾是作业评分。 (输出描述]按学号升序输出每位学生的学号和得分.[输入样例] 3 20191001 20191005 8 20191002 8 20191004 20191003 20191006 7 [输出样例) 20191001 8 20191002 9.6 20191003 7 20191004 7 20191005 8 20191006 7

Python for i in range ()用法详解

for i in range()是Python编程中常见的控制流语句，它结合range()函数提供了灵活的循环机制。通过调整range()的参数，你可以控制循环的起始、结束和步长，从而适应不同的编程需求。在实际编程中，for循环...

下面是一个用Python编程求阶乘和数的例子： def factorial(n): if n == 0 or n ==

digits = [int(digit) for digit in str(n)] factorial_sum = sum(factorial(digit) for digit in digits) return factorial_sum # 测试 num = 145 result = factorial_sum(num) print("阶乘和数为:", result) ...

import math a=int(input()) n=int(input()) k=0 total=0 for i in range(n): total=total+pow(10,k) print(total)帮我改错

for i in range(n): digit = (i + 1) % 10 # 对于每一位，取对应的整数 total += digit * pow(10, k) # 将当前位相乘并累加 k += 1 # 移动到下一位，每次循环增加幂次 # 输出最终结果 print(a * total) 在...

如果n大于3，n=int(input()) for i in range(10(n-1),10n): s=0 for j in str(i): s+=int(j)**n if s==i: print(i）错在哪

这段代码的问题在于，当 n ... for i in range(10**(n-1), 10**n): s = 0 for j in str(i): s += int(j)**n if s == i and i in [153, 370, 371, 407]: print(i) 这样就能正确输出 n 位数的所有水仙花数了。

优化这段代码：n=int(input()) list_a=[] sum=0 for i in range(n): row = input().split( ) list_a.append([int(x) for x in row]) for j in range(n): for k in range(n): if j==k or j+k==n-1: sum+=list_a[j][k] print("{:.2f}".format(sum))

for i in range(n): row = list(map(int, input().split())) list_a[i] = row sum = np.sum(list_a.diagonal()) + np.sum(np.fliplr(list_a).diagonal()) - list_a[n//2][n//2] print("{:.2f}".format(sum)) ...

n=int(input()) for i in range(n): scores=map(int,input().split()) print(max(scores))优化缩短运行时间

你可以使用列表解析式来取代 for 循环，同时使用内置函数 map() 和 max()，...print(*[max(map(int, input().split())) for _ in range(int(input()))]) 这样可以减少循环次数和代码行数，从而优化缩短运行时间。

import collections def solve_method(n: int) -> None: asc = True list_ = collections.deque() x = 1 for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] head = "" for ints in list_: content = head for j in range(len(ints)): num = ints[j] content += str(num) content += "" (4 - len(str(num))) if j != len(ints) - 1: content += " " res.append(content) head += " " for s in reversed(res): print(s) if name == "main": n = int(input()) solve_method(n) 改写以上代码，python

for i in range(1, n + 1): arr = [0] * i if asc: for j in range(i): arr[j] = x x += 1 else: for j in range(i - 1, -1, -1): arr[j] = x x += 1 list_.appendleft(arr) asc = not asc res = [] ...

n=int(input()) def fun1(n): d=round(sum([i / (2*i - 1) for i in range(1, n+1)]), 3) return d print(fun1(n)) 纠错

odd_sum = sum(i for i in range(1, n + 1, 2)) # 奇数序列 even_sum = sum(range(2, 2*n, 2)) # 偶数序列 # 如果even_sum为0，意味着n为0或奇数，此时无意义 if even_sum == 0: return "Invalid input: For ...

n = int(input("请输入整数的个数：")) lst = [] for i in range(n): x = int(input("请输入一个整数：")) lst.append(x) def bubble_sort(arr): n = len(arr) for i in range(n): for j in range(0, n - i - 1): if arr[j] > arr[j + 1]: arr[j], arr[j + 1] = arr[j + 1], arr[j] return arr lst=bubble_sort(lst)问题在哪，为什最后不会出现数列

for i in range(n): while True: try: x = int(input("请输入一个整数：")) lst.append(x) break except ValueError: print("输入不是整数，请重新输入！") def bubble_sort(arr): n = len(arr) if n <= 1...

n=eval(input()) N=int(n) j=0 while j<5: for i in range(2,N): if N%i==0: N=N+1 else: j=j+1 if j<5: print(N,end=",") N=N+1 else: print(N,end="")

for i in range(2, int(N ** 0.5) + 1): if N % i == 0: is_prime = False break if is_prime: count += 1 if count < 5: print(N, end=",") else: print(N) N += 1 这段代码可以正常输出 5 个质数...

while(True): a = int(input()) b = [int(input()) for _ in range(a)] def gzl(n, m): total = sum(b[n-1:m]) return 1 if total % 3 == 0 else 0 count = sum([gzl(i, j) for i in range(1, a+1) for j in range(i+1, a+1)]) count += sum([1 for x in b if x % 3 == 0]) print(count)运行显示while(True): a = int(input()) b = [int(input()) for _ in range(a)] def gzl(n, m): total = sum(b[n-1:m]) return 1 if total % 3 == 0 else 0 count = sum([gzl(i, j) for i in range(1, a+1) for j in range(i+1, a+1)]) count += sum([1 for x in b if x % 3 == 0]) print(count)

count = sum([gzl(i, j) for i in range(1, a+1) for j in range(i+1, a+1)]) count += sum([1 for x in b if x % 3 == 0]) print(count) 在这个例子中，我们增加了一个终止条件，当输入的 a 为 0 时，程序...

n = [] while True: a = input("Please enter a number to make a number_list or 'q' to quit:") if a != 'q': b = int(a) n.append(b) else: break num = int(input("Please enter a certain number :")) for i in range(len(n)): if n[i] < num: flag = 0 else: flag = 1 if flag == 0: print("Check", num, "in", n, ", the result is False") else: print("Check", num, "in", n, ", the result is True")找到错误并改正

for i in range(len(n)): if n[i] == num: flag = 1 break if flag == 0: print("Check", num, "in", n, ", the result is False") else: print("Check", num, "in", n, ", the result is True") 在这个...

纠错import bisect def min_operations(a, b): f = [0] * (n + 1) for i in range(1, n + 1): j = i - 1 while j > 0 and a[j] > b[i - 1]: j -= 1 f[i] = f[i - 1] + (i - j - 1) ans = float('inf') for i in range(n): cnt = i + 1 + n - bisect.bisect_left(b, a[i] + 1) ans = min(ans, cnt + f[n] - f[i + 1]) return ans t = int(input()) for _ in range(t): n = int(input()) a = list(map(int, input().split())) b = list(map(int, input().split())) print(min_operations(a, b))

for i in range(n): cnt = i + 1 + n - bisect.bisect_left(b, a[i] + 1) ans = min(ans, cnt + f[n] - f[i + 1]) return ans t = int(input()) for _ in range(t): n = int(input()) a = list(map(int, ...

n = int(input()) m = list(map(int, input().split())) cnt = 1 ans = 1 for i in range(len(m)): if m[i+1] == m[i] + 1: cnt+=1 if cnt > ans: ans = cnt else: cnt = 0 print(ans)优化代码，解决list out of index

for i in range(len(m)-1): if m[i+1] == m[i] + 1: cnt += 1 if cnt > ans: ans = cnt else: cnt = 1 print(ans) 这样，你就可以避免出现索引溢出的问题，并正确计算连续递增序列的最大长度。

n = int(input("请输入n的值：")) m = for i in range(1, n+1): if i % 2 == 1: m += i else: m -= i print("m的值为：", m)

for i in range(1, n+1): if i % 2 == 1: m += i else: m -= i print("m的值为：", m) 该程序的作用是计算从1到n之间的奇数项加起来的和，偶数项减去的和。其中，n的值由用户输入。程序通过循环遍历1到n...

n = int(input("请输入n：")) x = 0 sum = 0 for i in range(1, n + 1): x = ((-1) ** (i + 1)) / i sum+= x print(sum)

for i in range(1, n + 1): x = ((-1) ** (i + 1)) / Decimal(i) sum += x print(sum) 在代码中，我们首先导入了 decimal 模块，并使用 getcontext() 函数设置精度为 50。然后，将 x 和 sum 的初始值...

import math t=int(input()) while t>0: sum = 0 n,m=map(int,input().split()) for i in range(n,m+1): k=round(int(math.sqrt(i))) if k*k==i: sum+=i print(sum) t-=1哪里有问题

for i in range(n, m + 1): if int(math.sqrt(i)) ** 2 == i: total += i print(total) 这个版本中，我们将循环变量名从 i 改为了 _，因为实际上在循环体内并不需要使用它；将 sum 改为了 total；将 while ...

def primelist(n): for i in range(2,n+1): m=int(i**0.5) for j in range(2,m+1): if i%j==0: break else: 【1】 if name=='main': n=eval(input()) for i in 【2】: print(i, end=' ')

python print(i, end=' ') This line of code will print the prime number i to the console. The missing code at the line marked with "【2】" should be the following: python primelist(n) ...

一个python程序class Solution: def twoSum(self, nums: list[int], target: int)-> list[int]: n = len(nums) for i in range(n): for j in range(i + 1, n): if nums[i] + nums[j] == target: return [i, j]如何实现手动输入nums得到target

可以使用input函数手动输入nums和target，然后将其转换为int... for i in range(n): for j in range(i + 1, n): if nums[i] + nums[j] == target: return [i, j] s = Solution() print(s.twoSum(nums, target))

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Python for i in range ()用法详解

下面是一个用Python编程求阶乘和数的例子： def factorial(n): if n == 0 or n ==

import math a=int(input()) n=int(input()) k=0 total=0 for i in range(n): total=total+pow(10,k) print(total)帮我改错

如果n大于3，n=int(input()) for i in range(10**(n-1),10**n): s=0 for j in str(i): s+=int(j)**n if s==i: print(i）错在哪

优化这段代码：n=int(input()) list_a=[] sum=0 for i in range(n): row = input().split( ) list_a.append([int(x) for x in row]) for j in range(n): for k in range(n): if j==k or j+k==n-1: sum+=list_a[j][k] print("{:.2f}".format(sum))

n=int(input()) for i in range(n): scores=map(int,input().split()) print(max(scores))优化缩短运行时间

n=int(input()) def fun1(n): d=round(sum([i / (2*i - 1) for i in range(1, n+1)]), 3) return d print(fun1(n)) 纠错

n=eval(input()) N=int(n) j=0 while j<5: for i in range(2,N): if N%i==0: N=N+1 else: j=j+1 if j<5: print(N,end=",") N=N+1 else: print(N,end="")

n = int(input()) m = list(map(int, input().split())) cnt = 1 ans = 1 for i in range(len(m)): if m[i+1] == m[i] + 1: cnt+=1 if cnt > ans: ans = cnt else: cnt = 0 print(ans)优化代码，解决list out of index

n = int(input("请输入n的值：")) m = for i in range(1, n+1): if i % 2 == 1: m += i else: m -= i print("m的值为：", m)

n = int(input("请输入n：")) x = 0 sum = 0 for i in range(1, n + 1): x = ((-1) ** (i + 1)) / i sum+= x print(sum)

import math t=int(input()) while t>0: sum = 0 n,m=map(int,input().split()) for i in range(n,m+1): k=round(int(math.sqrt(i))) if k*k==i: sum+=i print(sum) t-=1哪里有问题

def primelist(n): for i in range(2,n+1): m=int(i**0.5) for j in range(2,m+1): if i%j==0: break else: 【1】 if __name__=='__main__': n=eval(input()) for i in 【2】: print(i, end=' ')

一个python程序class Solution: def twoSum(self, nums: list[int], target: int)-> list[int]: n = len(nums) for i in range(n): for j in range(i + 1, n): if nums[i] + nums[j] == target: return [i, j]如何实现手动输入nums得到target

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如果n大于3，n=int(input()) for i in range(10(n-1),10n): s=0 for j in str(i): s+=int(j)**n if s==i: print(i）错在哪

def primelist(n): for i in range(2,n+1): m=int(i**0.5) for j in range(2,m+1): if i%j==0: break else: 【1】 if name=='main': n=eval(input()) for i in 【2】: print(i, end=' ')