用devc++写一个井字棋游戏

好的，下面是一个简单的井字棋游戏的代码，使用了 Dev-C++ 编译器：

#include <iostream>
using namespace std;

char square[10] = {'0','1','2','3','4','5','6','7','8','9'};

int checkwin();
void board();

int main()
{
    int player = 1, i, choice;
    char mark;
    do {
        board();
        player = (player % 2) ? 1 : 2;
        cout << "Player " << player << ", enter a number: ";
        cin >> choice;
        mark = (player == 1) ? 'X' : 'O';
        if (choice == 1 && square[1] == '1')
            square[1] = mark;
        else if (choice == 2 && square[2] == '2')
            square[2] = mark;
        else if (choice == 3 && square[3] == '3')
            square[3] = mark;
        else if (choice == 4 && square[4] == '4')
            square[4] = mark;
        else if (choice == 5 && square[5] == '5')
            square[5] = mark;
        else if (choice == 6 && square[6] == '6')
            square[6] = mark;
        else if (choice == 7 && square[7] == '7')
            square[7] = mark;
        else if (choice == 8 && square[8] == '8')
            square[8] = mark;
        else if (choice == 9 && square[9] == '9')
            square[9] = mark;
        else {
            cout << "Invalid move!" << endl;
            player--;
            cin.ignore();
            cin.get();
        }
        i = checkwin();
        player++;
    } while (i == -1);
    board();
    if (i == 1) cout << "==>\aPlayer " << --player << " wins!" << endl;
    else cout << "==>\aGame draw" << endl;
    cin.ignore();
    cin.get();
    return 0;
}

int checkwin()
{
    if (square[1] == square[2] && square[2] == square[3]) return 1;
    else if (square[4] == square[5] && square[5] == square[6]) return 1;
    else if (square[7] == square[8] && square[8] == square[9]) return 1;
    else if (square[1] == square[4] && square[4] == square[7]) return 1;
    else if (square[2] == square[5] && square[5] == square[8]) return 1;
    else if (square[3] == square[6] && square[6] == square[9]) return 1;
    else if (square[1] == square[5] && square[5] == square[9]) return 1;
    else if (square[3] == square[5] && square[5] == square[7]) return 1;
    else if (square[1] != '1' && square[2] != '2' && square[3] != '3'
          && square[4] != '4' && square[5] != '5' && square[6] != '6'
          && square[7] != '7' && square[8] != '8' && square[9] != '9')
        return 0;
    else return -1;
}

void board()
{
    system("cls");
    cout << "Tic Tac Toe" << endl;
    cout << "Player 1 (X) - Player 2 (O)" << endl << endl;
    cout << "  " << square[1] << " | " << square[2] << " | " << square[3] << endl;
    cout << " -----------" << endl;
    cout << "  " << square[4] << " | " << square[5] << " | " << square[6] << endl;
    cout << " -----------" << endl;
    cout << "  " << square[7] << " | " << square[8] << " | " << square[9] << endl << endl;
}

这个游戏使用了一个字符数组 `square` 来存储棋盘，其中每个元素的初始值为该位置的编号。游戏基本逻辑是：玩家输入一个数字，程序检查这个数字是否合法，如果合法则将对应的位置更新为当前玩家的棋子，然后检查游戏是否结束。如果游戏结束，程序会输出胜利者或者平局。如果游戏没有结束，则交换当前玩家，重复上述流程。

为了让界面看起来更清晰，我们在 `board()` 函数中使用了 `system("cls")` 命令清空了屏幕，然后输出了当前的棋盘状况。

由于井字棋是一个比较简单的游戏，所以这里的代码也比较简单，但是对于初学者来说，已经足够了。