用C语言写一个井字棋游戏

A：

#include <stdio.h>
#include <stdlib.h>

// 定义井字棋格子内容类型
enum GridContent {
    GridContentEmpty,
    GridContentCross,
    GridContentCircle
};

// 构建井字棋棋盘
typedef struct {
    enum GridContent content[3][3];
} TicTacToeBoard;

// 初始化井字棋棋盘
void init_board(TicTacToeBoard *board) {
    for (int i = 0; i < 3; ++i) {
        for (int j = 0; j < 3; ++j) {
            board->content[i][j] = GridContentEmpty;
        }
    }
}

// 输出井字棋棋盘
void print_board(TicTacToeBoard *board) {
    for (int i = 0; i < 3; ++i) {
        for (int j = 0; j < 3; ++j) {
            if (board->content[i][j] == GridContentEmpty) {
                printf(" ");
            } else if (board->content[i][j] == GridContentCross) {
                printf("X");
            } else if (board->content[i][j] == GridContentCircle) {
                printf("O");
            }

            if (j != 2) {
                printf("|");
            }
        }

        printf("\n");

        if (i != 2) {
            printf("-+-+-\n");
        }
    }
}

// 判断是否有一方获胜
int check_win(TicTacToeBoard *board, enum GridContent content) {
    // 判断行
    for (int i = 0; i < 3; ++i) {
        if (board->content[i][0] == content && board->content[i][1] == content && board->content[i][2] == content) {
            return 1;
        }
    }

    // 判断列
    for (int i = 0; i < 3; ++i) {
        if (board->content[0][i] == content && board->content[1][i] == content && board->content[2][i] == content) {
            return 1;
        }
    }

    // 判断对角线
    if (board->content[0][0] == content && board->content[1][1] == content && board->content[2][2] == content) {
        return 1;
    }

    if (board->content[0][2] == content && board->content[1][1] == content && board->content[2][0] == content) {
        return 1;
    }

    return 0;
}

// 执行游戏主循环
void run_game() {
    TicTacToeBoard board;
    init_board(&board);
    enum GridContent player1_content = GridContentCross;
    enum GridContent player2_content = GridContentCircle;
    enum GridContent cur_content = player1_content;

    while (1) {
        // 输出当前棋盘
        printf("\n");
        print_board(&board);

        // 让玩家输入下一步位置
        int row, col;
        printf("\nPlayer %s's turn (row, col): ", (cur_content == player1_content ? "1" : "2"));
        scanf("%d %d", &row, &col);

        // 检查输入是否合法
        if (row < 1 || row > 3 || col < 1 || col > 3) {
            printf("Invalid input! Please enter the position as row col, where row and col are integers between 1 and 3.\n");
            continue;
        }

        if (board.content[row - 1][col - 1] != GridContentEmpty) {
            printf("The position has already been taken! Please choose another one.\n");
            continue;
        }

        // 将指定位置标记为当前玩家的棋子
        board.content[row - 1][col - 1] = cur_content;

        // 检查是否有一方获胜
        if (check_win(&board, cur_content)) {
            printf("\nPlayer %s wins!\n", (cur_content == player1_content ? "1" : "2"));
            print_board(&board);
            break;
        }

        // 如果棋盘已满，宣布平局
        int is_tie = 1;
        for (int i = 0; i < 3; ++i) {
            for (int j = 0; j < 3; ++j) {
                if (board.content[i][j] == GridContentEmpty) {
                    is_tie = 0;
                    break;
                }
            }
            if (!is_tie) {
                break;
            }
        }
        if (is_tie) {
            printf("\nThe game is a tie!\n");
            print_board(&board);
            break;
        }

        // 切换到下一个玩家
        cur_content = (cur_content == player1_content ? player2_content : player1_content);
    }
}

int main() {
    run_game();
    return 0;
}

这个程序使用了结构体和枚举类型来构建、表示井字棋棋盘和格子内容。它包括了下列功能：

- 初始化棋盘
- 输出棋盘
- 判断是否有一方获胜
- 让玩家输入下一步位置，并检查输入是否合法
- 更新棋盘状态，并在必要时宣布获胜或平局
- 切换到下一个玩家

运行程序即可体验井字棋游戏的玩法！