typedef struct { float vel; float matrix_q[STATE_SIZE]; float matrix_r; float feedforward_ratio; float feedback_ratio; float steer_delta_limit; float lateral_preview_time; float min_preview_dis; int feedforward_preview_index; }LqrTable; LqrTable forward_paras[LQRTABLE_SIZE] = {{0.3, {1.0,0.01,1.0,0.01}, 0.1, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {0.8, {0.4,0.00,1.0,0.005}, 0.1, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {1.5, {0.02,0.006,0.2,0.01}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {2.0, {0.02,0.005,0.2,0.01}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {3.0, {0.4,0.005,1.0,0.005}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {4.0, {0.4,0.005,1.0,0.005}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {5.5, {0.4,0.005,1.0,0.005}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {7.0, {0.16,0.005,1.0,0.006}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {8.0, {0.1,0.005,1.0,0.006}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {10.0, {0.1,0.005,1.0,0.006}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {12.5, {0.1,0.005,1.1,0.006}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {15.0, {0.1,0.005,1.1,0.006}, 1.0, 1.0, 1.0, 10.0, 0.1, 0.1, 2}, {17.0, {0.005,0.005,0.01,0.006}, 1.0, 0.0, 1.0, 10.0, 0.1, 0.1, 2}, {20.0, {0.0001,0.0001,0.002,0.006}, 1.0, 0.0, 1.0, 10.0, 0.1, 0.1, 2} }; LqrTable current_paras_ = forward_paras[0];被提示表达式必须含有常量值
时间: 2023-10-15 20:03:57 浏览: 67
这个错误的原因是在定义数组时,使用了变量来指定数组的大小,而不是使用常量值。在C语言中,数组的大小必须是一个常量值,不能是变量。如果需要在运行时动态指定数组的大小,可以使用动态内存分配,例如使用malloc函数分配内存。
解决这个错误的方法是,将LQRTABLE_SIZE宏定义为一个常量值,例如:
```
#define LQRTABLE_SIZE 14
```
然后在定义数组时,使用这个常量值来指定数组的大小,例如:
```
LqrTable forward_paras[LQRTABLE_SIZE] = {...};
```
这样就可以避免这个错误了。
相关问题
typedef struct _packed { uint8_t id; float temp; uint8_t humi; }TempHumiSensor;
这段代码定义了一个名为TempHumiSensor的结构体,并使用typedef关键字为其创建了一个别名。
TempHumiSensor结构体包含了三个成员变量:
- id:一个无符号8位整数,用于存储传感器的ID。
- temp:一个浮点数,用于存储温度值。
- humi:一个无符号8位整数,用于存储湿度值。
使用_packed修饰符对结构体进行了紧凑布局,以减少内存的使用。这在某些嵌入式系统中非常有用,可以节省内存空间。
通过typedef关键字,该结构体被命名为TempHumiSensor,并可以直接使用TempHumiSensor作为类型声明,而不需要每次都写完整的结构体名。这样做可以简化代码,提高可读性。
typedef struct { char id[MAX_INFO_LENGTH]; char name[MAX_INFO_LENGTH]; char address[MAX_INFO_LENGTH]; char contact[MAX_INFO_LENGTH]; char phone[MAX_INFO_LENGTH]; } Producer; typedef struct { char type[MAX_INFO_LENGTH]; char producer_id[MAX_INFO_LENGTH]; int quantity; float price; char date[MAX_INFO_LENGTH]; } Material; typedef struct { char id[MAX_INFO_LENGTH]; char name[MAX_INFO_LENGTH]; char address[MAX_INFO_LENGTH]; char contact[MAX_INFO_LENGTH]; char phone[MAX_INFO_LENGTH]; } Recipient; typedef struct { char recipient_id[MAX_INFO_LENGTH]; char material_type[MAX_INFO_LENGTH]; int quantity; char date[MAX_INFO_LENGTH]; char producer_id[MAX_INFO_LENGTH]; int received;
这段代码中定义了四个结构体,分别是Producer、Material、Recipient和一个未命名的结构体。这些结构体中都包含了一些成员变量,用来存储相关的信息。
Producer结构体包含了生产者的ID、名称、地址、联系人和电话等信息,Material结构体包含了材料的类型、生产者ID、数量、价格和日期等信息,Recipient结构体包含了接收者的ID、名称、地址、联系人和电话等信息。
而最后一个未命名的结构体中包含了接收者ID、材料类型、数量、日期、生产者ID和是否已接收等信息,这个结构体可能用来存储记录材料发放和接收的信息。
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