运用牛顿二元迭代法在Matlab求解theta1和theta2，rb*cos(theta1+mu)+(p*theta1+rou*cos(lambadab)-z)/sin(lambadab)*cos(lambadab)*sin(theta1+mu)+rou*sin(lambadab)*sin(theta1+mu)==rb*cos(theta2+mu)+(p*theta2+rou*cos(lambadab)+z)/sin(lambadab)*cos(lambadab)*sin(theta2+mu)+rou*sin(lambadab)*sin(theta2+mu); rb*cos(theta1+mu)-(p*theta1+rou*cos(lambadab)-z)/sin(lambadab)*cos(lambadab)*cos(theta1+mu)-rou*sin(lambadab)*sin(theta1+mu)==-rb*sin(theta2+mu)+(p*theta2+rou*cos(lambadab)+z)/sin(lambadab)*cos(lambadab)*cos(theta2+mu)+rou*sin(lambadab)*cos(theta2+mu);

首先，将方程转化为形式f(theta1,theta2)=0。可以定义一个函数f，其中包含两个方程：

function F = f(X)
mu = X(1);
theta1 = X(2);
theta2 = X(3);
rb = X(4);
p = X(5);
rou = X(6);
lambadab = X(7);
z = X(8);

F(1) = rb*cos(theta1+mu)+(p*theta1+rou*cos(lambadab)-z)/sin(lambadab)*cos(lambadab)*sin(theta1+mu)+rou*sin(lambadab)*sin(theta1+mu)-rb*cos(theta2+mu)-(p*theta2+rou*cos(lambadab)+z)/sin(lambadab)*cos(lambadab)*sin(theta2+mu)-rou*sin(lambadab)*sin(theta2+mu);
F(2) = rb*cos(theta1+mu)-(p*theta1+rou*cos(lambadab)-z)/sin(lambadab)*cos(lambadab)*cos(theta1+mu)-rou*sin(lambadab)*sin(theta1+mu)+rb*sin(theta2+mu)-(p*theta2+rou*cos(lambadab)+z)/sin(lambadab)*cos(lambadab)*cos(theta2+mu)-rou*sin(lambadab)*cos(theta2+mu);
end

然后使用Matlab内置的函数`fsolve`进行求解。代码如下：

mu = 0;
theta1 = 0;
theta2 = 0;
rb = 1;
p = 2;
rou = 3;
lambadab = 4;
z = 5;

X0 = [mu, theta1, theta2, rb, p, rou, lambadab, z];

options = optimoptions('fsolve','Display','iter');
X = fsolve(@f,X0,options);

这里将初始值设置为0，可以根据具体情况进行修改。使用`optimoptions`设置`fsolve`的选项，包括显示和迭代次数等。最终求解结果存储在向量X中。