#include <iostream> #include <cstdlib> #include <cstring> #include <vector> #include <algorithm> using namespace std; string Left[3]; string Right[3]; string Res[3]; bool isFalse(char coin,bool isLight) { string a; a.push_back(coin); for (int i=0;i<3;i++){ string l=Left[i],r=Right[i]; if(!isLight) swap(l,r); switch (Res[i][0]){ case 'e': if(l.find(a)!=string::npos||r.find(a)!=string::npos) return false; break; case 'u': if(r.find(a)==string::npos) return false; break; case 'd': if(l.find(a)==string::npos) return false; break; } } return true; } int main() { int t,i,j,k; cin>>t; while(t--) { for(i=0;i<3;i++) cin>>Left[i]>>Right[i]>>Res[i]; for (char c='A';c<='L';c++){ if (isFalse(c,true)){ cout << c << " is the counterfeit coin and it is light. "<<endl; break; } else if(isFalse(c,false)){ cout << c << " is the counterfeit coin and it is heavy. "<<endl; break; } } } return 0; }把上述代码变成python语言

以下是将上述代码转换为 Python 语言的版本：

def is_false(coin, is_light):
    for i in range(3):
        l = left[i]
        r = right[i]
        if not is_light:
            l, r = r, l
        if res[i][0] == 'e':
            if coin in l or coin in r:
                return False
        elif res[i][0] == 'u':
            if coin not in r:
                return False
        elif res[i][0] == 'd':
            if coin not in l:
                return False
    return True

t = int(input())
for _ in range(t):
    left = []
    right = []
    res = []
    for _ in range(3):
        l, r, result = input().split()
        left.append(l)
        right.append(r)
        res.append(result)
    
    for c in range(ord('A'), ord('L')+1):
        c = chr(c)
        if is_false(c, True):
            print(c, "is the counterfeit coin and it is light.")
            break
        elif is_false(c, False):
            print(c, "is the counterfeit coin and it is heavy.")
            break

请注意，我仅将代码从 C++ 转换为 Python，但未对逻辑进行任何更改。如果原始代码存在问题，转换后的代码也可能存在相同的问题。