编写Java程序,模拟甲、乙、丙、丁四人玩"过七"游戏。甲从1开始报数,其余人一次报下一个数,如果数字包含7或者为7的倍数,则该人喊“过”,输出100以内的报数过程。
时间: 2024-09-23 17:15:56 浏览: 18
为了编写这个Java程序,我们可以创建一个简单的类`Player`来代表每个人,并定义一个方法来检查数字是否符合条件。然后我们再创建一个主类`Game`来控制游戏流程。下面是代码的一个简略示例:
```java
public class Player {
private int currentNumber;
public Player(String name) {
this.currentNumber = 1;
}
public void play() {
while (currentNumber <= 100) {
System.out.println(name + ": " + currentNumber);
if (containsSeventeen(currentNumber)) {
System.out.println(name + "喊过!");
break;
}
currentNumber++;
}
}
private boolean containsSeventeen(int number) {
return number % 7 == 0 || String.valueOf(number).contains("7");
}
}
public class Game {
public static void main(String[] args) {
Player playerA = new Player("甲");
Player playerB = new Player("乙");
Player playerC = new Player("丙");
Player playerD = new Player("丁");
for (Player player : Arrays.asList(playerA, playerB, playerC, playerD)) {
player.play();
}
}
}
```
在这个例子中,`play()`方法会持续报数直到遇到7或其倍数。`containsSeventeen()`方法用于检查数字是否包含7或能被7整除。