循环赛日程表的算法设计
时间: 2023-11-09 07:08:37 浏览: 227
基于C++的循环赛日程表算法设计.zip
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算法描述:
1. 当n=2时,直接安排一场比赛。
2. 当n>2时,将n个选手分成两组,分别进行循环赛,每组的比赛日程表可以递归地使用该算法得到。
3. 将两组选手的比赛日程表合并,得到完整的比赛日程表。
4. 对于奇数n,将其中一个选手固定不动,其他n-1个选手进行循环赛,最后再让这个选手与其他选手轮流比赛。
比赛日程表:
当n=10时,可以将10个选手分成两组:1-5和6-10。每组进行5天的循环赛,得到以下比赛日程表:
第一组:
1 vs 2 3 vs 4 5 vs 6 7 vs 8 9 vs 10
1 vs 3 2 vs 5 4 vs 7 6 vs 9 8 vs 10
1 vs 4 2 vs 6 3 vs 8 5 vs 10 7 vs 9
1 vs 5 2 vs 7 3 vs 9 4 vs 10 6 vs 8
1 vs 6 2 vs 8 4 vs 9 5 vs 7 3 vs 10
第二组:
6 vs 7 8 vs 9 10 vs 1 2 vs 3 4 vs 5
6 vs 8 7 vs 10 1 vs 4 3 vs 5 2 vs 9
6 vs 9 7 vs 1 2 vs 4 5 vs 8 3 vs 10
6 vs 10 8 vs 1 3 vs 4 2 vs 5 7 vs 9
7 vs 8 9 vs 1 4 vs 6 3 vs 2 5 vs 10
将两组的比赛日程表合并,得到完整的比赛日程表:
1 vs 6 2 vs 8 4 vs 9 5 vs 7 3 vs 10
6 vs 7 8 vs 9 10 vs 1 2 vs 3 4 vs 5
1 vs 5 2 vs 7 3 vs 9 4 vs 10 6 vs 8
7 vs 10 1 vs 4 3 vs 5 2 vs 9 6 vs 9
2 vs 5 4 vs 7 6 vs 10 8 vs 1 3 vs 8
5 vs 10 7 vs 1 2 vs 4 3 vs 6 8 vs 9
1 vs 4 2 vs 6 3 vs 8 5 vs 9 7 vs 10
6 vs 8 7 vs 9 1 vs 3 2 vs 10 4 vs 6
3 vs 4 5 vs 8 6 vs 9 7 vs 1 2 vs 7
4 vs 9 5 vs 6 1 vs 2 3 vs 7 8 vs 10
7 vs 8 9 vs 1 4 vs 6 3 vs 2 5 vs 10
2 vs 3 4 vs 5 6 vs 7 8 vs 10 1 vs 9
3 vs 5 1 vs 7 2 vs 9 4 vs 10 6 vs 8
1 vs 2 3 vs 7 4 vs 8 5 vs 10 6 vs 9
2 vs 4 6 vs 7 8 vs 10 1 vs 3 5 vs 9
3 vs 6 4 vs 7 5 vs 8 1 vs 10 2 vs 8
4 vs 6 5 vs 7 1 vs 8 2 vs 10 3 vs 9
5 vs 6 1 vs 9 2 vs 8 3 vs 10 4 vs 7
1 vs 3 2 vs 5 4 vs 7 6 vs 9 8 vs 10
6 vs 10 8 vs 1 3 vs 4 2 vs 5 7 vs 9
1 vs 6 2 vs 8 4 vs 9 5 vs 7 3 vs 10
7 vs 10 1 vs 4 3 vs 5 2 vs 9 6 vs 9
2 vs 5 4 vs 7 6 vs 10 8 vs 1 3 vs 8
5 vs 10 7 vs 1 2 vs 4 3 vs 6 8 vs 9
1 vs 4 2 vs 6 3 vs 8 5 vs 9 7 vs 10
6 vs 8 7 vs 9 1 vs 3 2 vs 10 4 vs 6
3 vs 4 5 vs 8 6 vs 9 7 vs 1 2 vs 7
4 vs 9 5 vs 6 1 vs 2 3 vs 7 8 vs 10
7 vs 8 9 vs 1 4 vs 6 3 vs 2 5 vs 10
2 vs 3 4 vs 5 6 vs 7 8 vs 10 1 vs 9
3 vs 5 1 vs 7 2 vs 9 4 vs 10 6 vs 8
1 vs 2 3 vs 7 4 vs 8 5 vs 10 6 vs 9
2 vs 4 6 vs 7 8 vs 10 1 vs 3 5 vs 9
3 vs 6 4 vs 7 5 vs 8 1 vs 10 2 vs 8
4 vs 6 5 vs 7 1 vs 8 2 vs 10 3 vs 9
5 vs 6 1 vs 9 2 vs 8 3 vs 10 4 vs 7
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