这段代码是什么意思for n = 1:50 if mod(n,7) continue end disp(['Divisible by 7: ' num2str(n)]) end
时间: 2024-06-02 08:10:23 浏览: 13
这段代码的意思是,从1到50循环遍历每个数,如果这个数不能被7整除,那么就跳过这个数,否则就输出这个数是能被7整除的数。其中 mod(n,7) 是用来判断 n 是否能被 7 整除的函数,如果能整除,返回 0,否则返回非零值,这里用 if mod(n,7) 来判断 n 是否能被 7 整除,如果不能整除,就执行 continue 跳过这个数,否则输出这个数是能被 7 整除的数。
相关问题
Loops and flow control. Make function called loopTest(N) that loops through the values 1 through N and for each number n it should display ‘n is divisible by 2’, ‘n is divisible by 3’, ‘n is divisible by 2 AND 3’ or ‘n is NOT divisible by 2 or 3’. Use a for loop, the function mod or rem to figure out if a number is divisible by 2 or 3, and num2str to convert each number to a string for displaying. You can use any combination of if, else, and elseif.
Sure, here is the code for the `loopTest` function:
```
function loopTest(N)
%LOOPTEST Loops through the values 1 through N and displays whether each number is divisible by 2, 3, both, or neither.
for n = 1:N
if mod(n, 2) == 0 && mod(n, 3) == 0
disp([num2str(n), ' is divisible by 2 AND 3']);
elseif mod(n, 2) == 0
disp([num2str(n), ' is divisible by 2']);
elseif mod(n, 3) == 0
disp([num2str(n), ' is divisible by 3']);
else
disp([num2str(n), ' is NOT divisible by 2 or 3']);
end
end
end
```
You can call this function with any positive integer `N` to test it. For example, `loopTest(10)` would loop through the values 1 through 10 and display the appropriate message for each number.
I hope this helps! Let me know if you have any questions.
def _not_divisible(n): return lambda x: x % n > 0
这是一个 Python 的 lambda 函数,用于判断一个数是否能被 n 整除。它返回一个函数对象,这个函数输入一个参数 x,判断 x 是否能被 n 整除,如果不能整除则返回 True,否则返回 False。这个 lambda 函数可以用于筛选质数,例如:
```python
def primes(n):
primes_list = []
sieve = [True] * n
for p in range(2, n):
if sieve[p]:
primes_list.append(p)
for multiple in range(p*p, n, p):
sieve[multiple] = False
return primes_list
primes_list = primes(20)
print(primes_list) # [2, 3, 5, 7, 11, 13, 17, 19]
primes_list = filter(_not_divisible(2), range(2, 20))
print(list(primes_list)) # [3, 5, 7, 11, 13, 17, 19]
```
在上面的代码中,我们先生成了小于 20 的质数列表 primes_list,然后使用 filter 函数和 _not_divisible(2) 函数筛选出大于等于 2 小于 20 的质数列表。
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