if(n%i=0,i!=1,i=n) x=n/i+i
时间: 2023-05-27 14:08:06 浏览: 69
There are a few issues with the code snippet provided. Here is a corrected version:
for i in range(2, n):
if n % i == 0 and i != 1:
x = n / i
# do something with x
Explanation:
- The condition `n % i == 0` checks if `i` is a factor of `n`.
- The condition `i != 1` excludes the trivial case where `i = 1` (every number is divisible by 1).
- The assignment `x = n / i` calculates the quotient `n/i`.
- The block of code following the `if` statement (represented by `# do something with x`) will be executed if the condition is true. You can replace this comment with the actual code you want to execute with `x` as the variable holding the quotient.
相关问题
#include<iostream> using namespace std; int main() { int n; cin>>n; int z[101],m[101],s=1,sum=0,x,yu; for(int i=0;i<n;i++) { scanf("%d/%d",&z[i],&m[i]); } for(int i=0;i<n;i++) { s*=m[i]; } for(int i=0;i<n;i++) { z[i]*=s; z[i]/=m[i]; } for(int i=0;i<n;i++) { sum+=z[i]; } x=int(sum/s); yu=sum%s; for(int i=2;i<=yu&&i<=s;i++) { if(yu%i==0&&s%i==0) { yu/=i; s/=i; i--; } } if(yu!=0&&x!=0) cout<<x<<" "<<yu<<"/"<<s<<endl; if(x!=0&&yu==0) cout<<x<<endl; if(x==0&&yu!=0) cout<<yu<<"/"<<s<<endl; return 0; }解决浮点错误
在进行除法运算时,需要注意除数不能为0。如果除数有可能为0,可以进行判断,避免浮点错误的出现。
例如,在上面的代码中,第一个for循环中,如果输入的分母m[i]为0,则会导致除法运算产生浮点错误。可以在输入时进行判断,如果m[i]==0,则直接跳过该次循环。
另外,还有一种情况是在进行约分时,如果分子或分母为0,则会出现浮点错误。可以在约分之前先判断分子z[i]是否为0,如果为0,则不进行约分。
修改后的代码如下:
```c++
#include<iostream>
using namespace std;
int main() {
int n;
cin >> n;
int z[101], m[101], s = 1, sum = 0, x, yu;
for (int i = 0; i < n; i++) {
scanf("%d/%d", &z[i], &m[i]);
if (m[i] == 0) { // 如果分母为0,则跳过该次循环
i--;
n--;
}
}
for (int i = 0; i < n; i++) {
s *= m[i];
}
for (int i = 0; i < n; i++) {
if (z[i] != 0) { // 如果分子为0,则不进行约分
z[i] *= s;
z[i] /= m[i];
}
}
for (int i = 0; i < n; i++) {
sum += z[i];
}
x = int(sum / s);
yu = sum % s;
for (int i = 2; i <= yu && i <= s; i++) {
if (yu % i == 0 && s % i == 0) {
yu /= i;
s /= i;
i--;
}
}
if (yu != 0 && x != 0)
cout << x << " " << yu << "/" << s << endl;
if (x != 0 && yu == 0)
cout << x << endl;
if (x == 0 && yu != 0)
cout << yu << "/" << s << endl;
return 0;
}
```
将以下java代码转换为C++代码:public class { public static void main(String[] args) { int j=0; for (int i=1;i<10000000;i++){ if (BaseConversion(i)){ j++; if (j==2023){ System.out.println(i);//215040 break; } } } } public static boolean BaseConversion(int n){ //十进制 int sum=0; int x=n; while (x!=0){ sum+=(x%10); x/=10; } if (n%sum!=0) return false; //二进制 sum=0; x=n; while (x!=0){ sum+=(x%2); x/=2; } if (n%sum!=0) return false; //八进制 sum=0; x=n; while (x!=0){ sum+=(x%8); x/=8; } if (n%sum!=0) return false; //十六进制 int[] arr={0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}; sum=0; x=n; while (x!=0){ sum+=(arr[x%16]); x/=16; } if (n%sum!=0) return false; return true; } }
以下是将给定的 Java 代码转换为 C++ 代码的版本:
```cpp
#include <iostream>
bool BaseConversion(int n) {
// 十进制
int sum = 0;
int x = n;
while (x != 0) {
sum += (x % 10);
x /= 10;
}
if (n % sum != 0)
return false;
// 二进制
sum = 0;
x = n;
while (x != 0) {
sum += (x % 2);
x /= 2;
}
if (n % sum != 0)
return false;
// 八进制
sum = 0;
x = n;
while (x != 0) {
sum += (x % 8);
x /= 8;
}
if (n % sum != 0)
return false;
// 十六进制
int arr[] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
sum = 0;
x = n;
while (x != 0) {
sum += (arr[x % 16]);
x /= 16;
}
if (n % sum != 0)
return false;
return true;
}
int main() {
int j = 0;
for (int i = 1; i < 10000000; i++) {
if (BaseConversion(i)) {
j++;
if (j == 2023) {
std::cout << i << std::endl; // 215040
break;
}
}
}
return 0;
}
```
希望这可以帮助到你!