n=int(input()) count=0 while n>0: count += 1 n-=1 if count!=0 and count%3==0: n+=1 print(count) 与下面代码的区别 n=int(input()) count=0 while n>0: n-=1 if count!=0 and count%3==0: n+=1 count += 1 print(count)
时间: 2023-05-28 10:05:00 浏览: 70
Null is a term used in computer programming and databases to represent a value that does not exist or is undefined. It is often used to indicate the absence of a value or to indicate an error. In programming languages, null is often used as a placeholder value or to indicate that a variable has not been assigned a value. In databases, null is used to represent missing or unknown data.
相关问题
n = int(input()) m = input() num = n count = 0 while num > 0: number = num % 16 if number == 0: if m == "0": count = count + 1 elif number == 1: if m == "1": count = count + 1 elif number == 2: if m == "2": count = count + 1 elif number == 3: if m == "3": count = count + 1 elif number == 4: if m == "4": count = count + 1 elif number == 5: if m == "5": count = count + 1 elif number == 6: if m == "6": count = count + 1 elif number == 7: if m == "7": count = count + 1 elif number == 8: if m == "8": count = count + 1 elif number == 9: if m == "9": count = count + 1 elif number == 10: if m == "a": count = count + 1 elif number == 11: if m == "b": count = count + 1 elif number == 12: if m == "c": count = count + 1 elif number == 13: if m == "d": count = count + 1 elif number == 14: if m == "e": count = count + 1 elif number == 15: if m == "f": count = count + 1 num = int(num / 16) print(count)
这段代码的主要作用是统计一个十进制数 n 在十六进制下某一位的出现次数。代码首先接收一个十进制数 n 和一个十六进制数 m,然后将 n 逐位转换成十六进制数,将转换后的每一位与 m 进行比较,如果相等,则将计数器 count 加一。最后输出 count 的值,即 m 在 n 的十六进制表示中出现的次数。需要注意的是,该代码中的十六进制数是用字符串形式表示的。
将本段python代码转为c语言代码: n = int(input()) necklace = input() count = 0 for i in range(n): color = necklace[i % n] if color == 'w': count += 1 else: j = i while necklace[j % n] == color: j += 1 count += j - i print(count)
以下是将给定的 Python 代码转换成 C 语言代码的过程:
```c
#include <stdio.h>
#include <string.h>
int main() {
int n, count = 0, i, j;
char necklace[100000];
scanf("%d", &n);
scanf("%s", necklace);
for (i = 0; i < n; i++) {
char color = necklace[i % n];
if (color == 'w') {
count++;
} else {
j = i;
while (necklace[j % n] == color) {
j++;
}
count += j - i;
}
}
printf("%d\n", count);
return 0;
}
```
注意,这里我们假设项链字符串的最大长度为 100000。