输入用逗号分隔的多个数，输出最小绝对值python

要实现输入用逗号分隔的多个数并输出最小绝对值的Python程序，你可以按照以下步骤操作：

**方法一：逐个元素求绝对值并比较**

def min_abs_value(numbers):
    # Split the input string by comma and convert to a list of floats
    num_list = [float(num.strip()) for num in input().split(",")]

    # Initialize min_abs with a large number (正无穷)
    min_abs = float('inf')

    # Iterate over the numbers, calculate their absolute values, and update min_abs if necessary
    for num in num_list:
        abs_num = abs(num)
        if abs_num < min_abs:
            min_abs = abs_num

    return min_abs

# 示例输入: "－1, 3, 1"
min_val = min_abs_value("-1, 3, 1")
print(min_val)  # 输出: 1.0

**方法二：使用内置`sorted`函数结合`abs`函数**

def min_abs_value_bis(numbers):
    # Convert the input string to a list of floats after splitting by comma
    num_list = [float(num.strip()) for num in input().split(",")]

    # Return the smallest absolute value from the sorted list
    return min(sorted([abs(num) for num in num_list]))

# 示例输入同上
min_val_bis = min_abs_value_bis("-1, 3, 1")
print(min_val_bis)  # 输出: 1.0