轨迹压缩之Douglas-Peucker算法之C++实现
时间: 2024-01-06 12:04:04 浏览: 20
好的,我可以为您提供Douglas-Peucker算法的C++实现代码。以下是一个简单的实现:
```c++
#include <iostream>
#include <vector>
#include <cmath>
using namespace std;
// 定义点结构体
struct Point {
double x;
double y;
};
// 计算点到直线的垂直距离
double distance(Point a, Point b, Point c) {
double ABx = b.x - a.x;
double ABy = b.y - a.y;
double numerator = ABx * (a.y - c.y) - ABy * (a.x - c.x);
if (numerator < 0) numerator = -numerator;
double denominator = sqrt(ABx * ABx + ABy * ABy);
return numerator / denominator;
}
// 实现Douglas-Peucker算法
void douglas_peucker(vector<Point>& points, int startIndex, int endIndex, double epsilon, vector<int>& result) {
double dmax = 0;
int index = 0;
int n = points.size();
for (int i = startIndex + 1; i < endIndex; i++) {
double d = distance(points[startIndex], points[endIndex], points[i]);
if (d > dmax) {
index = i;
dmax = d;
}
}
if (dmax > epsilon) {
vector<int> res1;
vector<int> res2;
douglas_peucker(points, startIndex, index, epsilon, res1);
douglas_peucker(points, index, endIndex, epsilon, res2);
for (int i = 0; i < res1.size() - 1; i++) {
result.push_back(res1[i]);
}
for (int i = 0; i < res2.size(); i++) {
result.push_back(res2[i]);
}
} else {
result.push_back(startIndex);
result.push_back(endIndex);
}
}
int main() {
vector<Point> points = {
{1, 1},
{2, 3},
{3, 5},
{4, 4},
{5, 6},
{6, 7},
{7, 8},
{8, 9},
{9, 10},
{10, 10},
};
vector<int> result;
douglas_peucker(points, 0, points.size() - 1, 1, result);
for (int i = 0; i < result.size(); i++) {
cout << points[result[i]].x << ", " << points[result[i]].y << endl;
}
return 0;
}
```
该实现基于递归,并使用了点到直线的垂直距离计算方法来决定是否压缩该线段。您可以自行调整epsilon参数来控制压缩程度。