题目要求:有一个5x5数组,从键盘为它输入数据并按照5x5的显示方式输出数组,求出主对角线各元素之和,并求出该数组中的最大的数所在的行列号。
时间: 2024-02-11 20:04:34 浏览: 17
好的,让我来帮你解决这个问题。
首先,我们可以通过以下代码从键盘输入5x5的数组:
```python
arr = []
for i in range(5):
row = input().split()
arr.append([int(num) for num in row])
```
然后,我们可以按照5x5的显示方式输出数组:
```python
for row in arr:
for num in row:
print(num, end=' ')
print()
```
接下来,我们可以计算主对角线各元素之和:
```python
sum_diag = 0
for i in range(5):
sum_diag += arr[i][i]
```
最后,我们可以找到数组中的最大的数所在的行列号:
```python
max_val = arr[0][0]
max_row = 0
max_col = 0
for i in range(5):
for j in range(5):
if arr[i][j] > max_val:
max_val = arr[i][j]
max_row = i
max_col = j
```
完整的代码如下所示:
```python
arr = []
for i in range(5):
row = input().split()
arr.append([int(num) for num in row])
for row in arr:
for num in row:
print(num, end=' ')
print()
sum_diag = 0
for i in range(5):
sum_diag += arr[i][i]
max_val = arr[0][0]
max_row = 0
max_col = 0
for i in range(5):
for j in range(5):
if arr[i][j] > max_val:
max_val = arr[i][j]
max_row = i
max_col = j
print("主对角线各元素之和为:", sum_diag)
print("最大的数为:", max_val)
print("最大的数所在的行列号为:", max_row, max_col)
```
希望能够帮助到你!