利用顺序栈实现十进制转二进制。代码

好的，以下是利用顺序栈实现十进制转二进制的代码，供你参考：

class Stack:
    def __init__(self):
        self.items = []

    def is_empty(self):
        return len(self.items) == 0

    def push(self, item):
        self.items.append(item)

    def pop(self):
        if not self.is_empty():
            return self.items.pop()

    def peek(self):
        if not self.is_empty():
            return self.items[-1]

    def size(self):
        return len(self.items)

def decimal_to_binary(decimal_num):
    stack = Stack()

    while decimal_num > 0:
        remainder = decimal_num % 2
        stack.push(remainder)
        decimal_num //= 2

    binary_num = ""

    while not stack.is_empty():
        binary_num += str(stack.pop())

    return binary_num

# 测试代码
print(decimal_to_binary(10)) # 输出 1010
print(decimal_to_binary(23)) # 输出 10111